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Natali5045456 [20]

2 years ago

10

For 520.0 ml of a buffer solution that is 0.175 m in hc2h3o2 and 0.165 m in nac2h3o2, calculate the initial ph and the final ph

after adding 0.020 mol of hcl.

1 answer:

alisha [4.7K]2 years ago

3 0

KWIJRJHO0907 X 023KO

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Explanation:

We are going to do 4 successive dilutions. In each dilution, we will apply the dilution rule.

C₁.V₁=C₂.V₂

where,

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<u>First dilution</u>

C₁ = 3.1 × 10⁻⁵ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL

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<u>Second dilution</u>

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$C_{2}=\frac{C_{1}.V_{1}}{V_{2}} =\frac{5.0 \times 10^{-10}M \times 1.00mL }{40.00mL} =1.3 \times 10^{-11}M$

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