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2 years ago

True or False: As the ice warms up, the molecules get more energy and move around more from place to place to form liquid water.

Chemistry

2 answers:

Arada [10]2 years ago

7 0

The answer is TRUE.

Hope it helps.

Gwar [14]2 years ago

4 0

True the molecules get more energy

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How many electrons are there in carbonate ion, CO3^-2?

NISA [10]

It should be 24 electrons

3 0

2 years ago

Calculate the final molarity of HCl the resulting solution when 5.56 mL of 4.108 M HCl is added to 4.44 mL of water.

puteri [66]

The final molarity of HCl is 2.284 M

We'll begin by listing what was given from the question. This is shown below:

Initial volume (V₁) = 5.56 mL

Initial Molarity (M₁) = 4.108 M

Final volume (V₂) = 5.56 + 4.44 = 10 mL

<h3>Final Molarity (M₂) =? </h3>

The final molarity of the HCl solution can be obtained by using the dilution formula as illustrated below:

4.108 × 5.56 = M₂ × 10

22.84048 = M₂ × 10

Divide both side by 10

M₂ = 22.84048 / 10

Therefore, final molarity of the HCl solution is 2.284 M.

Learn more: brainly.com/question/6103588

5 0

2 years ago

Critique Maria’s laboratory safety procedures.

Svetllana [295]

1.No eating in the lab
2.No running around in the lab
3.Wear gloves while performing experiments
4.Clen your hands before you leave the lab

3 0

3 years ago

How many moles of NH3 can be produced from 12.0 mol of H2 and excess N2? Express your answer numerically in moles. View Availabl

VladimirAG [237]

Answer:

A) 8.00 mol NH₃

B) 137 g NH₃

C) 2.30 g H₂

D) 1.53 x 10²⁰ molecules NH₃

Explanation:

Let us consider the balanced equation:

N₂(g) + 3 H₂(g) ⇄ 2 NH₃(g)

Part A

3 moles of H₂ form 2 moles of NH₃. So, for 12.0 moles of H₂:

$12.0molH_{2}.\frac{2molNH_{3}}{3molH_{2}} =8.00molNH_{3}$

Part B:

1 mole of N₂ forms 2 moles of NH₃. And each mole of NH₃ has a mass of 17.0 g (molar mass). So, for 4.04 moles of N₂:

$4.04molN_{2}.\frac{2molNH_{3}}{1molN_{2}} .\frac{17.0gNH_{3}}{1molNH_{3}} =137gNH_{3}$

Part C:

According to the <em>balanced equation</em> 6.00 g of H₂ form 34.0 g of NH₃. So, for 13.02g of NH₃:

$13.02gNH_{3}.\frac{6.00gH_{2}}{34.0gNH_{3}} =2.30gH_{2}$

Part D:

6.00 g of H₂ form 2 moles of NH₃. An each mole of NH₃ has 6.02 x 10²³ molecules of NH₃ (Avogadro number). So, for 7.62×10⁻⁴ g of H₂:

$7.62 \times 10^{-4} gH_{2}.\frac{2molNH_{3}}{6.00gH_{2}} .\frac{6.02\times 10^{23}moleculesNH_{3} }{1molNH_{3}}=1.53\times10^{20}moleculesNH_{3}$

3 0

3 years ago

Which of kbr or ch3br is likely to have the higher normal boiling point?

allsm [11]

Answer:

KBr

Explanation

KBr is an ionic compound which have very high BP since they exist as 3D crystals

Methyl Bromide, CH3Br. is a covalent compound which have low BP since they exist as individual molecules

8 0

2 years ago