Answer:
25306
Step-by-step explanation:
a=starting value = 20000
r=\text{rate = }4\% = 0.04
r=rate = 4%=0.04
\text{Exponential Growth:}
Exponential Growth:
b=1+r=1+0.04=1.04
b=1+r=1+0.04=1.04
\text{Write Exponential Function:}
Write Exponential Function:
y=20000(1.04)^x
y=20000(1.04)
x
Put it all together
\text{Plug in time for x:}
Plug in time for x:
y=20000(1.04)^{6}
y=20000(1.04)
6
y= 25306.38037
y=25306.38037
So Roger flight left at exactly 9.27:am and it will land at 1:05pm
So count on to 12:27 will be 3 hours and subtract from 5 because 65 is 05 3hours and 38mins
Let us model this problem with a polynomial function.
Let x = day number (1,2,3,4, ...)
Let y = number of creatures colled on day x.
Because we have 5 data points, we shall use a 4th order polynomial of the form
y = a₁x⁴ + a₂x³ + a₃x² + a₄x + a₅
Substitute x=1,2, ..., 5 into y(x) to obtain the matrix equation
| 1 1 1 1 1 | | a₁ | | 42 |
| 2⁴ 2³ 2² 2¹ 2⁰ | | a₂ | | 26 |
| 3⁴ 3³ 3² 3¹ 3⁰ | | a₃ | = | 61 |
| 4⁴ 4³ 4² 4¹ 4⁰ | | a₄ | | 65 |
| 5⁴ 5³ 5² 5¹ 5⁰ | | a₅ | | 56 |
When this matrix equation is solved in the calculator, we obtain
a₁ = 4.1667
a₂ = -55.3333
a₃ = 253.3333
a₄ = -451.1667
a₅ = 291.0000
Test the solution.
y(1) = 42
y(2) = 26
y(3) = 61
y(4) = 65
y(5) = 56
The average for 5 days is (42+26+61+65+56)/5 = 50.
If Kathy collected 53 creatures instead of 56 on day 5, the average becomes
(42+26+61+65+53)/5 = 49.4.
Now predict values for days 5,7,8.
y(6) = 152
y(7) = 571
y(8) = 1631
Answer:
PUPPY DOGGIE
Step-by-step explanation:
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