I need help please!! 15 Points! NEED BY 8:30

Duc works for a salary of $2,200 per month. His computed hourly rate of pay is $13.75 per hour. Although Duc earns a salary, he

Slav-nsk [51]

Net pay is take-home pay or pay after tax so 2200 per month assume that 2200 is salary without overtime counted 13.75 per hour overtime=1 and 1/2 times regular so worked 14 overtime hours or 14 times 1 and 1/2 times 13.75=288.75 add to salary 2488.75 take taxes so take 15% and 6.2% and 1.45% and $85, so add the percents up and subtract 15+6.2+1.45=22.65% subtract from 100 to find how much left 100-22.65=77.35% left multiply this to total salary which is overtimepay+salary=2488.75 77.35%=0.7735 0.7735 times 2488.75=1925.05 then subtract health insurance premiums which is 85 1925.05-85=1840.05 his net pay was $1840.05

3 0

3 years ago

Read 2 more answers

Can someone give me the answers to problems a-l? I already finished it but I don't have an answer key so I want to check with so

svetlana [45]

If we approach 1 from the left, we're using the blue function, but if we approach 1 from the right, we're using the green function. So, we have

$\displaystyle \lim_{x\to 1^-}f(x) = 0,\quad\lim_{x\to 1^+}f(x) = -1$

Since the left and right limits are different, the limit

$\displaystyle \lim_{x\to 1}f(x)$

does not exist.

When we approach 0, we always use the blue function. Both halves of the blue function tend to 1 as x approaches zero. So, in this case, we have

$\displaystyle \lim_{x\to 0^-}f(x) = \lim_{x\to 0^+}f(x) = 1 = \lim_{x\to 0}f(x)$

Note that the fact that, by definition, we have $f(0)=2$ doesn't mean that the limit is wrong, or that it doesn't exist. It simply means that the function is not continuous, because we have

$\displaystyle f(x_0)\neq \lim_{x\to x_0}f(x)$

As for -2, x can approach this value only from the left, because the function is not defined between -2 and -1. So, we have

$\displaystyle \lim_{x\to -2}f(x) = \lim_{x\to -2^-}f(x) 0-\infty$

The limit as x approaches 3 is similar to the one where x approaches zero: the function is not defined at x=3, but the limit from both sides approaches -1:

$\displaystyle \lim_{x\to 3^-}f(x) = \lim_{x\to 3^+}f(x) = -1 = \lim_{x\to 3}f(x)$