Ask question

Ask question

All categories

2 years ago

15

While driving on the highway, Fiona averages 60 miles per hour. In the city, she averages 30 miles per hour. On a trip to her gr

andmother's house, Fiona drives 312 hours on the highway and 112 hours in the city.

1 answer:

jok3333 [9.3K]2 years ago

6 0

52.1 miles per hour would be your answer.

You might be interested in

Can someone help me please

pshichka [43]

Answer: 56 times

Pls mark brainleist i really need it

7 0

1 year ago

Select all sets in which the number

strojnjashka [21]

Answer:

A

E

Step-by-step explanation:

a rational number can be expressed as fraction. well, that is what the number 8/9 is.

so, A is a correct option.

as such it is automatically also a member of the real numbers (which is a superset of rational numbers). so, E is a correct option.

all other options are wrong.

8/9 is not a natural number (1, 2, 3, 4, ...).

it is not a whole number (0, 1, 2, 3, 4, ...).

it is not an integer (... , -2, -1, 0, 1, 2, 3, ...).

and as it is a rational number, it is automatically not an irrational number.

7 0

2 years ago

When a new machine is not functioning properly, 15% of the items produced are defective. Assume that we will randomly select 5 p

cestrela7 [59]

Answer:

P(X<=2) = 0.9736

Step-by-step explanation: Please find the attached file for the solution

7 0

2 years ago

A child has 4 wooden blocks. How many different ways can she stack 3 of them into a tower?

faltersainse [42]

Answer:

Step-by-step explanation:

To find the number of different ways she can stack 3 of them in a tower, we need to use the formula:

$_{n}P_{k}=\dfrac{n!}{(n-k)!}$

n = 4

k = 3

$_{n}P_{k}=\dfrac{4!}{(4-3)!}$

$_{n}P_{k}=\dfrac{4!}{1!}$

$_{n}P_{k}=\dfrac{4*3*2*1!}{(1)!}$

$_{n}P_{k}=\dfrac{4*3*2*1!}{1}$

$_{n}P_{k}=\dfrac{24}{1}$

7 0

2 years ago

Deshawn has two bags of marbles. The first bag has 2 blue, 3 orange, and 5 red. The second bag has 4 pink, 10 blue, and 6 brown.

madreJ [45]

Answer: 0.1

Step-by-step explanation:

Given

Bag-I has 2 blue,3 orange, 5 red

Bag-II has 4 Pink,10 blue, 6 brown

No of ways of choosing a blue marble from bag-I

$\Rightarrow ^2C_1$

Total no of ways of choosing a marble from bag-I

$\Rightarrow ^{10}C_1$

No of ways of choosing a blue marble from bag-II

$\Rightarrow ^{10}C_1$

Total no of ways of choosing a marble from bag-II

$\Rightarrow ^{20}C_1$

The probability that he will pull out a blue marble from each bag is

$\Rightarrow P=\text{Probability of pulling a blue marble from bag-I}\times \text{Probability of pulling a blue out bag-II}$

$\Rightarrow P=\dfrac{^2C_1}{^{10}C_1}\times \dfrac{^{10}C_1}{^{20}C_1}\\\\\Rightarrow P=\dfrac{2}{10}\times \dfrac{10}{20}=\dfrac{1}{10}$

3 0

2 years ago