Answer:
y = 2x + 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 1, 0) and (x₂, y₂ ) = (0, 2) ← coordinates of intercepts
m = = 2
Note the line crosses the y- axis at (0, 2) ⇒ c = 2
y = 2x + 2 ← equation of line
I hope this helps you...
Answer:
Problem 4: y = -8x+b
Problem 5: C: 3x-2
Step-by-step explanation:
<u>Problem 4:</u>
The given line is in slope intercept form.
The slope-intercept form is:
Here the co-efficient of x is the slope of the line. Comparing the given equation with general form
m = -8
Two parallel lines have same slope so the slope of line will be -8.
b can be any positive or negative integer as we don't know any point on the line parallel to given line.
<u>Problem 5:</u>
Slope = 3
y-intercept = -2
Slope intercept of line is given by:
here m is slope and b is y-intercept
Putting the values
Option C: y=3x-2 is the correct answer
Hence,
Problem 4: y = -8x+b
Problem 5: C: 3x-2
We will write and solve an equation that expresses the given relation. Let x represent the angle measure. Its complement is (90-x).
... x =(1/4)(90 -x)
Subtract x and simplify
... 0 = (90/4) - (5/4)x
Divide by the coefficient of x, which is -5/4.
... 0 = -18 +x
Add the opposite of the constant.
... 18 = x
The angle is 18°.
<h3>2.</h3>The attachment shows the intersction of road AB with road CD.
<em>Supplementary angles:</em> ∠CXA and ∠CXB; ∠BXC and ∠BXD; ∠DXA and ∠DXB; ∠AXC and ∠AXD.
<em>Complementary angles:</em> none
<em>Vertical angles:</em> ∠AXC and ∠BXD; ∠BXC and ∠AXD.
