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2 years ago

Please help quick it’s a test

Mathematics

1 answer:

disa [49]2 years ago

8 0

The rate must be in DECIMAL form and the time must be in YEARS

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Piecewise function help

Vlad1618 [11]

Nothing is mentioned...how am I supposed to help you?

3 0

3 years ago

Elena has a washing machine with a 20 gallon capacity. She always uses a 20 gram measure of soap for every 10 gallons of water.

baherus [9]

Answer:

For $20$ minutes Elena add water to correct the error.

Step-by-step explanation:

The capacity of the washing machine is $20$ gallons.

She uses $20$ gram soap for $10$ gallon of water

Her son by mistake dissolved $60$ grams of soap to $10$ gallons of water.

$\[60\]-$ gram soap is right for $30$ gallons of water, thus $20$ gallon of water must be added more.

She pore water $2$ gallons per minute thus, $20$ gallons of water will take $10$ minutes.

Learn more about equations : brainly.com/question/20727602?referrer=searchResults

6 0

2 years ago

• Machine s is cleaned every 12 weeks. •Machine that is cleaned every 8 weeks. What is the fewest number of weeks that will pass

vfiekz [6]

Week 24,assuming that both machines are cleaned at week 0, because multiples of 12 are 12, 24,36. And multiples of 8 are 8, 16, 24. 24 is also the LCM.

7 0

3 years ago

Can someone help me ASAP plsssss

AlladinOne [14]

that is literally gibberish

4 0

3 years ago

In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home. Give the value of th

astra-53 [7]

Answer:

The value of the standard error for the point estimate is of 0.0392.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home.

This means that $n = 100, p = \frac{81}{100} = 0.81$

Give the value of the standard error for the point estimate.

This is s. So

$s = \sqrt{\frac{0.81*0.19}{100}} = 0.0392$

The value of the standard error for the point estimate is of 0.0392.

7 0

2 years ago