Let the capacity of bus be x students
And van be y students, now ;
From the given statements we get two equations ~
multiply the equation (2) with 2 [ it won't change the values ]
Now, deduct equation (1) from equation (3)
Therefore each bus can carry (x) = 45 students
Now, plug the value of x in equation (1) to find y ~
Hence, each van can carry (y) = 17 students in total.
Answer:
Step-by-step explanation:
Given :
Multiply numerator and denominator by 2 :
[Divide both sides by 5 as it is a common factor]
The first answer is 40 second 65 third 56 and then fourth 90
Answer:
B
Step-by-step explanation:
K=1/3=10
L=1/5=6
10+6=16
30-16=14
You have to combine like terms, so the variable (x, y, s, d, c....) and the exponents must be the same in order to combine them.
For example:
x² + x³ Since they don't have the same exponent, you can't combine them
y² + 3y² = 4y²
23x + x = 24x
4. 2s² + 1 + s² - 2s + 1 You can rearrange it if it makes it easier
2s² + s² - 2s + 1 + 1 = 3s² - 2s + 2
5. 5t² - 2t - 1 - (3t² - 5t + 7) Distribute/multiply the - to (3t² - 5t + 7)
5t² - 2t - 1 - 3t² + 5t - 7 = 2t² + 3t - 8
Do the same for #9 and #10, and you should get:
9. 2k² + 5k - 9
10. 6y³ - 7y² - 6y - 12
