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3 years ago

How do you do factor x²-49?

Mathematics

1 answer:

Allisa [31]3 years ago

3 0

Answer:

(x-7)*(x+7)

Step-by-step explanation:

49 can be factored as 7*7 = 7^2

x^2 - 49

= x^2 - 7^2

You also learned that a^2 - b^2 = (a-b) * (a+b), so in this case:

x^2 - 7^2 = (x-7) * (x+7)

So x^2 - 49 factored to become (x-7)*(x+7)

Hope this help you :3

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Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16

IrinaK [193]

Answer:

Jogging 6th time.

Step-by-step explanation:

We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.

We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.

We know that an arithmetic sequence is in form $a_n=a_1+(n-1)d$ , where,

$a_n$ = nth term of sequence,

$a_1$ = 1st term of sequence,

n = Number of terms in sequence,

d = Common difference.

Let us find common difference of our given sequence as:

$\frac{3}{8}-\frac{3}{16}\Rightarrow \frac{6}{16}-\frac{3}{16}=\frac{3}{16}$

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

$1$

Let us solve for n.

$1$

$1\cdot \frac{16}{3}$

$5.333$

$n>5.333$

We can also write next terms of our sequence as:

$\frac{3}{16},\frac{6}{16}, \frac{9}{16},\frac{12}{16},\frac{15}{16},\frac{18}{16}$

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.

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