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3 years ago

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2 answers:

Oksanka [162]3 years ago

7 0

I got uuuuuuuuuuuuuuuuuuuuuuuuuuuu

nlexa [21]3 years ago

4 0

Answer:

Line HG. This line will never cross line EF and it is on the same plane.

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Find an equation of the line that passes through the point (4, 3) and is perpendicular to the line 2x + 9y − 6 = 0.

vesna_86 [32]

Perpendicular has the reciprocal slope and u have to put the point given into point slope.

y-3=9/2(x-4)

(The slope of the original equation was -2/9)

3 0

3 years ago

2852.1 rounded to the nearest tenth of a mile

katrin2010 [14]

2852.1 rounded to the nearest tenth of a mile is still 2852.1

5 0

3 years ago

Read 2 more answers

Use the Chain Rule (Calculus 2)

atroni [7]

1. By the chain rule,

$\dfrac{\mathrm dz}{\mathrm dt}=\dfrac{\partial z}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial z}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}$

I'm going to switch up the notation to save space, so for example, $z_x$ is shorthand for $\frac{\partial z}{\partial x}$ .

$z_t=z_xx_t+z_yy_t$

We have

$x=e^{-t}\implies x_t=-e^{-t}$

$y=e^t\implies y_t=e^t$

$z=\tan(xy)\implies\begin{cases}z_x=y\sec^2(xy)=e^t\sec^2(1)\\z_y=x\sec^2(xy)=e^{-t}\sec^2(1)\end{cases}$

$\implies z_t=e^t\sec^2(1)(-e^{-t})+e^{-t}\sec^2(1)e^t=0$

Similarly,

$w_t=w_xx_t+w_yy_t+w_zz_t$

where

$x=\cosh^2t\implies x_t=2\cosh t\sinh t$

$y=\sinh^2t\implies y_t=2\cosh t\sinh t$

$z=t\implies z_t=1$

To capture all the partial derivatives of $w$ , compute its gradient:

$\nabla w=\langle w_x,w_y,w_z\rangle=\dfrac{\langle1,-1,1\rangle}{\sqrt{1-(x-y+z)^2}}}=\dfrac{\langle1,-1,1\rangle}{\sqrt{-2t-t^2}}$

$\implies w_t=\dfrac1{\sqrt{-2t-t^2}}$

2. The problem is asking for $\frac{\partial z}{\partial x}$ and $\frac{\partial z}{\partial y}$ . But $z$ is already a function of $x,y$ , so the chain rule isn't needed here. I suspect it's supposed to say "find $\frac{\partial z}{\partial s}$ and $\frac{\partial z}{\partial t}$ " instead.

If that's the case, then

$z_s=z_xx_s+z_yy_s$

$z_t=z_xx_t+z_yy_t$

as the hint suggests. We have

$z=\sin x\cos y\implies\begin{cases}z_x=\cos x\cos y=\cos(s+t)\cos(s^2t)\\z_y=-\sin x\sin y=-\sin(s+t)\sin(s^2t)\end{cases}$

$x=s+t\implies x_s=x_t=1$

$y=s^2t\implies\begin{cases}y_s=2st\\y_t=s^2\end{cases}$

Putting everything together, we get

$z_s=\cos(s+t)\cos(s^2t)-2st\sin(s+t)\sin(s^2t)$

$z_t=\cos(s+t)\cos(s^2t)-s^2\sin(s+t)\sin(s^2t)$

8 0

3 years ago

A 10-ounce container of chocolate chips can be used to make 4 desserts.

Mademuasel [1]

Answer:

10/4 =10/4 ounces

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Use the net to find the surface area of the regular pyramid

Alja [10]

Answer:

151.9 if the side length of the pentagon/ base of each triangle is 6 m

Step-by-step explanation:

if the side length of the pentagon/ base of each triangle is 6 m then it is a pretty simple question, we just need to add the surface area of the base pentagon and each triangle.

We have the area of the base, so we just need the triangles. The area of a triangle is .5bh, where the base of a triangle here is one side of the pentagon and the height is that indicated red 6. so that means one triangle has an area of .5*6*6 or 18. There are 5 triangles total so that means that with all the triangles there is an area of 90. Adding that to 61.9 gets us 151.9. let me know if you need any more help.

8 0

3 years ago