Question

Find the y-intercept and the axis of symmetry of f(x)=ax2+2ax+3.

Answer 1

Answer:

$y= cx^2 +dx +e$

We see that:

$c = a, d= 2a , e= 3$

The axis of symmetry is defined by this formula:

$X= - \frac{d}{2c}$

And replacing we got:

$X= -\frac{2a}{2a}= -1$

Thn the axis of symmetry would be X=-1

Step-by-step explanation:

For this case we have the following function:

$y = ax^2 +2ax +3$

If we compare this function with the general expression of a quadratic formula given by:

$y= cx^2 +dx +e$

We see that:

$c = a, d= 2a , e= 3$

The axis of symmetry is defined by this formula:

$X= - \frac{d}{2c}$

And replacing we got:

$X= -\frac{2a}{2a}= -1$

Thn the axis of symmetry would be X=-1