Let
x----------> charge per hour to rent a jet sky in dollars
y----------> the total cost to rent a jet sky in dollars
we know that
<u>First Jet Sky Company</u>
---------> equation 
<u>Second Jet Sky Company</u>
---------> equation 
we know that
To find the number of hours for which the costs are the same
equate equation and equation
The intersection both graphs is the solution of the problem
using a graph tool
see the attached figure
the intersection point is 
That means
For 
the cost of the rent is 
in both companies
therefore
<u>the answer is</u>
Answer: 127 11/12
Step-by-step explanation:
1. 1/2 + 3/4 = 2/3
Change 1/2 by by multiplying by 2 to get a common denominator of fourths.
2/4 + 3/4 = 2/3?
5/4 = 2/3?
no
2. 5/8 - 1/4
Change 1/4 by by multiplying by 2 to get a common denominator of eighths.
5/8 - 2/8 = 3/8?
3/8 = 3/8 ?
yes
3/8 x 10 = 30/8
3. 4/5 +7/10 = 1 1/2
Change 4/5 by multiplying by 2 to get a common denominator tenths.
8/10 + 7/10 = 1 1/2?
15 /10 = 1 1/2?
yes
1 1/2 x 10 = 25
4. 2 1/3 - 1 5/6 = 1/6
Change 1/3 by multiplying by 2 to get a common denominator sixths.
2 2/6 - 1 5/6 = 1/6?
3/6 = 1/6
no
100 -2/3 - 1/6 + 30/8 + 25
multiply the thirds by 8. Sixths by 4. Eighths by 3 to get a common denomonator of 24ths.
100 - 16/24 - 4/24 + 90/ 24 + 25 = 125 70/24
create mixed number
127 22/24
reduce
127 11/12
Answer:2x
Step-by-step explanation:
Answer:
You didn't put which hauling companies, but I think I have the same question has you.
EZ would charge <u>980</u>
Happy hauling would charge <u>1000</u>
Plug in -1 for x
and you'll get this:
Solve it further and you'll get:
Therefore,
where x = -1
