Answer:
Step-by-step explanation:
29.8 ÷ 3 is 9.9333 repeating
Hey there! I'm happy to help!
Let's look at the factors of each of these numbers.
25
1,25
5,5
30
1,30
2,15
3,10
5,6
The greatest common factor between these is 5. Therefore, we divide 25+30 by 5 and put the 5 on the outside.
5(5+6).
This has the same value but it is just written differently.
Have a wonderful day! :D
The color that has the greatest difference between the theoretical and experimental probability is yellow.
<h3>Which color has the greatest difference?
</h3>
Theoretical probability of each color = number of color in each section / total number of sections
1/5 = 0.2
Experimental probability is based on the result of an experiment that has been carried out multiples times
Experimental probability
Experimental probability of choosing orange = 118 / 625 = 0.19
Difference = 0.2 - 0.19 = 0.01
Experimental probability of choosing purple = 137 / 625 = 0.22
Difference 0.22 - 0.2 = 0.02
Experimental probability of choosing brown = 122 / 625 = 0.20
0.2 - 0.2 = 0
Experimental probability of choosing yellow = 106 / 625 = 0.17
0.20 - 0.1696 = 0.0304
Experimental probability of choosing green = 142 / 625 = 0.23
0.2272 - 0.20 = 0.0272
To learn more about experimental probability, please check: brainly.com/question/23722574
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<u>Answer:</u>
<u>1. A. You allow the passenger to board his flight when the passenger has a weapon.</u>
<u>2. B. You select the passenger for further inspection when the passenger has no weapon.</u>
<u>Explanation:</u>
1. Remember, a Type I error in simple words means that the assumption "the passenger has a weapon" (null hypothesis) is <em>actually true,</em> but the airport security screener <em>incorrectly concluded it is false. </em>In other words, he assumed the passenger had no weapon and allowed the passenger to board his flight <u>when he actually did have one.</u>
<em>2. While, </em><em>a </em><em>Type II error </em><em>means that </em>the assumption "the passenger has a weapon" (null hypothesis) is <em>actually false, </em>but the airport security screener <em>incorrectly concluded it is true. </em>In other words, he assumed the passenger had a weapon and selected the passenger for further inspection <u>when he actually didn't have one.</u>
