The solution to the given expression negative four and one third ÷ two and one fifth is -1 32/33
<h3>Fraction division</h3>
negative four and one third ÷ two and one fifth
-4 1/3 ÷ 2 1/5
= -13/3 ÷ 11/5
- Multiply by the reciprocal of 11/5
- The reciprocal of 11/5 is 5/11
= -13/3 × 5/11
= (-13 × 5) / (3 × 11)
= -65 / 33
= -1 32/33
Therefore, the solution to the fraction is -1 32/33
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Since angles EFA, AFB, and BFC lie on a straight line, then they must add up to 180° (angle sum of a straight line)
So, 7x + 4 + 8x + 6 + 6x + 2 = 180
21x + 12 = 180
21x = 168
x = 8
A sum of 5 from two cubes is ALWAYS one odd and one even, so the condition does not change anything whatsoever.
To roll a 5, we can have (1,4),(2,3),(3,2),(4,1) out of a sample space of 36 outcomes. So the probability is 4/36, or 1/9.
Alberto can add all of the numbers of coins up to find the total number of coins. Now, you can add the recent total to 343 to get the FINAL amount of coins.
