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erastovalidia [21]
3 years ago
5

What is an equation of the line that passes through the point (-2,-8) and has the slope of 3

Mathematics
1 answer:
NeTakaya3 years ago
3 0

Answer:

y = 3x - 2

Step-by-step explanation:

y +8 = 3 (x + 2)

y + 8 = 3x + 6

y = 3x - 2

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Mrs. Baker uses 7.5 cups of sugar to make 168 cookies. To the nearest hundredth, what is the unit rate in cups of sugar per cook
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7 0
4 years ago
Write the standard form of the line passing through the following points (-5,1) and (0,-5)
Ronch [10]

Answer:

-6/5

Step-by-step explanation:

-5-1 / 0-(-5)

3 0
3 years ago
The center of a hyperbola is (−4,3) , and one vertex is (−4,7) . The slope of one of the asymptotes is 2.
Monica [59]

Answer:

The answer to your question is below

Step-by-step explanation:

C (-4, 3)

V (-4, 7)

asymptotes = 2 = \frac{b}{a}

- This is a vertical hyperbola, the equation is

       \frac{(y - k)^{2} }{a^{2} } + \frac{(x - h)^{2} }{b^{2} } = 1

slope = 2

a is the distance from the center to the vertex = 4

b = 2(4) = 8

       \frac{(y - 3)^{2} }{4^{2} } + \frac{(x + 4)^{2} }{8^{2} } = 1

       \frac{(y - 3)^{2} }{16} + \frac{(x + 4)^{2} }{64} = 1

7 0
3 years ago
Read 2 more answers
Two friends leave there houses and go towards each others, one friend runs 8 miles a hour, the other runs 7 miles an hour, there
natka813 [3]

hi there the answer is 7:30 see the picture

3 0
3 years ago
If the endpoints of the diameter of a circle are (−6, 6) and (6, −2), what is the standard form equation of the circle?
Varvara68 [4.7K]
1. Find the centre of the circle or the midpoint of the two numbers
(6-6/2}, (-2+6/2)
(0, 2)
2. Find radius using the distance formula
√<span>(6 - 2)² + (-6 - 0)²
</span>√4² + (-6)²
√16 + 36
√52
r = 7.21
3. Plug in
x² + (y - 2)² = 52

So it is option D 99% sure
6 0
3 years ago
Read 2 more answers
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