3 years ago

What is an equation of the line that passes through the point (-2,-8) and has the slope of 3

Mathematics

1 answer:

NeTakaya3 years ago

3 0

Answer:

y = 3x - 2

Step-by-step explanation:

y +8 = 3 (x + 2)

y + 8 = 3x + 6

y = 3x - 2

You might be interested in

Mrs. Baker uses 7.5 cups of sugar to make 168 cookies. To the nearest hundredth, what is the unit rate in cups of sugar per cook

vodomira [7]

Answer:0.04

Step-by-step explanation:

7 0

4 years ago

Write the standard form of the line passing through the following points (-5,1) and (0,-5)

Ronch [10]

Answer:

-6/5

Step-by-step explanation:

-5-1 / 0-(-5)

3 0

3 years ago

The center of a hyperbola is (−4,3) , and one vertex is (−4,7) . The slope of one of the asymptotes is 2.

Monica [59]

Answer:

The answer to your question is below

Step-by-step explanation:

C (-4, 3)

V (-4, 7)

asymptotes = 2 = $\frac{b}{a}$

- This is a vertical hyperbola, the equation is

$\frac{(y - k)^{2} }{a^{2} } + \frac{(x - h)^{2} }{b^{2} } = 1$

slope = 2

a is the distance from the center to the vertex = 4

b = 2(4) = 8

$\frac{(y - 3)^{2} }{4^{2} } + \frac{(x + 4)^{2} }{8^{2} } = 1$

$\frac{(y - 3)^{2} }{16} + \frac{(x + 4)^{2} }{64} = 1$

7 0

3 years ago

Read 2 more answers

Two friends leave there houses and go towards each others, one friend runs 8 miles a hour, the other runs 7 miles an hour, there

natka813 [3]

hi there the answer is 7:30 see the picture

3 0

3 years ago

If the endpoints of the diameter of a circle are (−6, 6) and (6, −2), what is the standard form equation of the circle?

Varvara68 [4.7K]

1. Find the centre of the circle or the midpoint of the two numbers
(6-6/2}, (-2+6/2)
(0, 2)
2. Find radius using the distance formula
√<span>(6 - 2)² + (-6 - 0)²
</span>√4² + (-6)²
√16 + 36
√52
r = 7.21
3. Plug in
x² + (y - 2)² = 52

So it is option D 99% sure

6 0

3 years ago

Read 2 more answers