Answer:
Lower confidence limit = 20.191
Step-by-step explanation:
Sample mean; x' = 22
Sample standard deviation; s = 5.5
Sample size; n = 50
Confidence interval = 99%
Since sample size > 30, we will use the formula;
CI = x' ± zs/√n
Where;
x' is sample mean
s is sample standard deviation
n is sample size
z is z-value of the confidence interval
From the table attached, z for 99% = 2.3263
Thus;
CI = 22 ± (2.3263 × 5.5)/√50
CI = 22 ± 1.809
CI = 23.809 or 20.191
Lower confidence limit = 20.191
Let the small number be x and the big number be y
x+y=49
x+2y=83
by solving simultaneously,
x=15 and y=34
Answer:
t = 0 and t = 2
Step-by-step explanation:
It is at rest when the velocity = 0
The velocity is the 1st derivative
So, x'(t) = 3t^2 - 6t = 0
3t(t - 2) = 0
t = 0 and t = 2
Answer:
first step is to minus 28.7 - 6.7=22 (I did the minus because I want to get the remaining length of the rope )
step 2 : is to divide 22 by 2 (because the question said they should divide it into two pieces )
then the answer you get from the division of 22/2 which is 11 that would be the final answer
meaning each tire swing is 11m
