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3 years ago

I need help with this

Mathematics

1 answer:

DedPeter [7]3 years ago

6 0

I remember some of this from 6th grade!
a.) the 7th graders have a smaller range compared to the 8th graders.
c.) 30 and 18 are the medians. Subtract them and you get 12.
Hope I could help partially

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2 years ago

2x + 8 = 3x + x + 18 how do i solve this

Gnoma [55]

Answer:

x=-10

Step-by-step explanation:

reorder the terms: 8+2x=18+3x

solve: 8+2x=18+3x

-3x -3x

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8-1x=18

-8. -8

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-1x= 10

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3 years ago

What are the solutions to 3n-1>8 or 4n+3 < -1? *

hammer [34]

Answer:

3’d

Step-by-step explanation:

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3 years ago

Find the lateral area for the pyramid with the equilateral base

likoan [24]

<h3>The lateral area for the pyramid with the equilateral base is 144 square units</h3>

Solution:

The given pyramid has 3 lateral triangular side

The figure is attached below

Base of triangle = 12 unit

Find the perpendicular

By Pythagoras theorem

$hypotenuse^2 = opposite^2 + adjacent^2$

Therefore,

$opposite^2 = 10^2 - 6^2\\\\opposite^2 = 100 - 36\\\\opposite^2 = 64\\\\opposite = 8$

Find the lateral surface area of 1 triangle

$\text{ Area of 1 lateral triangle } = \frac{1}{2} \times opposite \times base$

$\text{ Area of 1 lateral triangle } = \frac{1}{2} \times 8 \times 12\\\\\text{ Area of 1 lateral triangle } = 48$

Thus, lateral surface area of 3 triangle is:

3 x 48 = 144

Thus lateral area for the pyramid with the equilateral base is 144 square units

5 0

3 years ago

The midpoint of the coordinates (3, 15) and (20,8) is -

Nat2105 [25]

Answer:

The midpoint of the given coordinates is $(\frac{23}{2},\frac{23}{2})\ or\ (11.5,11.5)$ .

Step-by-step explanation:

We have given two coordinates (3,15) and (20,8).

Let we have given a line segment PQ whose P coordinate is (3,15) and Q coordinate is (20,8).

We have to find out the mid point M(x,y) of the line segment PQ.

Solution,

By the mid point formula of coordinates, which is;

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

On substituting the given values, we get;

$M(x,y)=(\frac{3+20}{2}, \frac{15+8}{2})\\\\M(x,y)=(\frac{23}{2},\frac{23}{2})$

We can also say that $M(x,y)=(11.5,11.5)$

Hence The midpoint of the given coordinates is $(\frac{23}{2},\frac{23}{2})\ or\ (11.5,11.5)$ .

3 0

3 years ago