Answer:
it will be the first one
Step-by-step explanation:
On a phone here and no access to paper but you must first find the midpoint of AC which is the average of the coordinates. The perpendicular bisector will have a gradient that multiplies by AC's gradient to make -1. This will obviously pass through its mid point so as long as you know how to use y=mx+c you should be good.
Answer:
<em>The perimeter of the fencing is 44 feet (Option D)</em>
Step-by-step explanation:
<u>Area and Perimeter</u>
A square shape of side length (a) has an area given by:
![A = a^2](https://tex.z-dn.net/?f=A%20%3D%20a%5E2)
And its perimeter is calculated as:
P = 4a
The area of Katrina's square garden is given as A=121 square feet. We need to calculate the side length by solving for a:
![a=\sqrt{121}](https://tex.z-dn.net/?f=a%3D%5Csqrt%7B121%7D)
a = 11 feet
Once we know the value of a, then we calculate the perimeter:
P = 4*11 = 44
The perimeter of the fencing is 44 feet (Option D)
<h2>
Answer:</h2>
<em>Angle 1 measures 25 degrees</em>
<h2>
Explanation:</h2>
Hello! Remember you have to write complete questions in order to get good and exact answers. Here I'll assume the diagram shown below. In that figure, we know that:
![\angle 1=? \\ \\ \angle 2=155^{\circ}](https://tex.z-dn.net/?f=%5Cangle%201%3D%3F%20%5C%5C%20%5C%5C%20%5Cangle%202%3D155%5E%7B%5Ccirc%7D)
The figure shows that these two angles are supplementary, so they add up to 180 degrees. Therefore:
![\angle 1+\angle 2=180^{\circ} \\ \\ Substituting \ \angle 2=155^{\circ}: \\ \\ \angle 1+155^{\circ}=180^{\circ} \\ \\ \\ Isolating \ \angle 1: \\ \\ \angle 1=180^{\circ}-155^{\circ} \\ \\ \boxed{\angle 1=25^{\circ}}](https://tex.z-dn.net/?f=%5Cangle%201%2B%5Cangle%202%3D180%5E%7B%5Ccirc%7D%20%5C%5C%20%5C%5C%20Substituting%20%5C%20%5Cangle%202%3D155%5E%7B%5Ccirc%7D%3A%20%5C%5C%20%5C%5C%20%5Cangle%201%2B155%5E%7B%5Ccirc%7D%3D180%5E%7B%5Ccirc%7D%20%5C%5C%20%5C%5C%20%5C%5C%20Isolating%20%5C%20%5Cangle%201%3A%20%5C%5C%20%5C%5C%20%5Cangle%201%3D180%5E%7B%5Ccirc%7D-155%5E%7B%5Ccirc%7D%20%5C%5C%20%5C%5C%20%5Cboxed%7B%5Cangle%201%3D25%5E%7B%5Ccirc%7D%7D)