Question

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Answer 1

Answer:

1.(k−4)(k+6)

Explain:Factor k2+2k−24

k2+2k−24

=(k−4)(k+6)

2.(2k+1)(2k−1)

Factor 4k2−1

4k2−1

=(2k+1)(2k−1)

3.(5b−3)(5b−3)

Explain: Factor 25b2−30b+9

25b2−30b+9

=(5b−3)(5b−3)

4.x=4 or x=-7

Let's solve your equation step-by-step.

x2+11x+28=0

Step 1: Factor left side of equation.

(x+4)(x+7)=0

Step 2: Set factors equal to 0.

x+4=0 or x+7=0

x=−4 or x=−7

is  5 to help solve or are they questions to?

Step-by-step explanation:

Answer 2

Answer:

1.  k^2+2k-24

1A. (k - 4) (k + 6)

2. 4k^2-1

2A. (2k + 1) (2k - 1)

3. 25b^2-30b+9

3A. (5b - 3)^2

4. x^2+11x+28=0

4A. x = (-4) OR (-7)

5. (3a+8)(3a^2-a-7)

5A. 9a^2 + 21a^2 - 29a - 56

Step-by-step explanation:

1.  k^2+2k-24

Factor using the AC factoring method.

k^2 = 2k

2k + 2k - 24

(k - 4) (k +6)

2. 4k^2-1

Use the Difference of Squares Formula: a^2 - b^2 = (a + b)(a - b)

2k = a

1 = b

(2k + 1)(2k - 1)

3. 25b^2-30b+9

Use the perfect square rule

(5b - 3)(5b - 3)

(5b - 3)^2

4. x^2+11x+28=0

Factor, by setting each factor equal to 0

x^2+11x+28=0

(x + 4)(x + 7) = 0

x = (-4) OR (-7)

5. (3a+8)(3a^2-a-7)

Simply, multiply each term in the first expression by each term in the second expression, and then simplify.

(3a+8)(3a^2-a-7)

9a^2 + 21a^2 - 29a - 56