Folding a paper will make it thickness become double from it before.
Unfolded paper has 1 thickness
1 times folded paper has 2 thickness
2 times folded paper has 4 thickness
3 times folded paper has 8 thickness
From here it is clear that the pattern is
![2^{n}](https://tex.z-dn.net/?f=%202%5E%7Bn%7D%20)
. SInce the paper is 0.1mm, then the function would be:
f(n)=
![2^{n}](https://tex.z-dn.net/?f=%202%5E%7Bn%7D%20)
x 0.1mm
<span>Here's the formula to find the area of a triangular prism: </span>
![SA=bh+2ls+lb](https://tex.z-dn.net/?f=SA%3Dbh%2B2ls%2Blb)
Now, let's define the variables.
b (base) = 3.6 mm
h (height) = 2.4 mm
l (length) = 5 mm
s (side length) = 3 mm
Next, plug the values in for the variables in the formula and solve.
![SA=3.6(2.4) + 2 (5)(3) + (5)(3.6)](https://tex.z-dn.net/?f=SA%3D3.6%282.4%29%20%2B%202%20%285%29%283%29%20%2B%20%285%29%283.6%29)
![SA=8.64+30+18](https://tex.z-dn.net/?f=SA%3D8.64%2B30%2B18)
![SA=56.64](https://tex.z-dn.net/?f=SA%3D56.64)
Answer: the surface area is
56.64 millimeters
hope this helps! ps, I labeled a diagram for you
I wish i could help but dont know the answer. I reccomend using mathpapa the website to help with math problems of all types
First answer should be correct ..
Step-by-step explanation:
As the triangles are similar so,
3/9 = 4/12 = 4.5/k
Taking 3/9 and 4.5/k Then
![\frac{3}{9} = \frac{4.5}{k} \\ \: cross \: multiply \\ k \: = \frac{9 \times 4.5}{3} \\ k \: = 13.5 \\hope \: it \: will \: help](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B9%7D%20%20%3D%20%20%5Cfrac%7B4.5%7D%7Bk%7D%20%20%5C%5C%20%20%5C%3A%20cross%20%5C%3A%20multiply%20%5C%5C%20k%20%5C%3A%20%20%3D%20%20%5Cfrac%7B9%20%5Ctimes%204.5%7D%7B3%7D%20%20%5C%5C%20k%20%5C%3A%20%20%3D%2013.5%20%5C%5Chope%20%5C%3A%20it%20%5C%3A%20will%20%5C%3A%20help)