Answer:
2
Step-by-step explanation:
You would use PEMDAS( parentheses exponents multiply adding subtracting) (1/2)4.
^
o.5×4
^
2
Answer:
9/2 if n goes to infinity and that the 2n^3 is under the whole expression
Step-by-step explanation:
Let me clear this .
find limit (9n^3 + 5*n - 2)/ (2n^3)
as n --> infinity
Did I put the parentheses in the right spot?
because if you leave it the way you did, then the whole expression goes to positive infinity as n goes to infinity But I will do this with parentheses
so
find limit (9n^3 + 5*n - 2)/ (2n^3)
simplify expression
limit (9/2) + 5/(2n^2) - 1/(n^3)
= (9/2) + 0 - 0
= (9/2)
Answer:
(a) 
(b) 
(c) 
Step-by-step explanation:
(a)



(b)


(c)


Hope this helps!
Answer:
A) 1/(3x+1)
Step-by-step explanation:
(x+2)/(x³+2x²-9x-18)÷(3x+1)/(x²-9)
(x+2)/(x+2)(x+3)(x-3)÷(3x+1)/(x+3)(x-3)
since it’s dividing by a fraction, invert and multiply
(x+2)/(x+2)(x+3)(x-3) times (x+3)(x-3)/(3x+1)
The (x+2)’s cancel out.
The (x+3)’s cancel out.
The (x-3)’s cancel out.
You are left with 1/(3x+1)
The total space in the parking lot is 1600 cars
It is mentioned that
parts of this parking is filled
Now we are required to find what is the three-fourths part of 1600
To find it we multiply
times 1600

= 
=
= 1200 cars
Hence 1200 cars fills the three-fourths of the car parking lot that has a capacity of 1600 cars