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GalinKa [24]
3 years ago
12

What is the value of

Mathematics
2 answers:
frozen [14]3 years ago
5 0
What is the value of what? 
Sedaia [141]3 years ago
4 0

this mb fam value of dis

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I NEED HELP PEOPLE!!!! WILL GIVE BRAINLIEST!!!!
Sauron [17]

Answer:

L(2,4)   M(3,1)   N(0,4)

Step-by-step explanation:

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4 years ago
You suspect that the spiciness of food served in a restaurant is positively correlated with number of soft drinks ordered. What
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<span>B) Observe several cases of people ordering food of varying spice-levels and number of soft drinks ordered. thats what i think though.</span>
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Addy has 51.79 pounds of dirt. She has buckets in her garage. Each bucket can hold 2.5 pounds of dirt. If she has 20 buckets wil
kirill [66]

Answer:

No

Step-by-step explanation:

20x2.5=50

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therefore there isn't enough buckets for all the dirt.

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3 years ago
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Writer and solve a real-word promblem involving the multiplication of a fraction and a whole number whose is between 10and15
pickupchik [31]
Give me an operation like the one you are talki ng about and I can solve it
8 0
3 years ago
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

3 0
2 years ago
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