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Marat540 [252]
3 years ago
13

The quotient of , x ≠ 0, is

Mathematics
1 answer:
Yakvenalex [24]3 years ago
5 0
Does anyone else here know the answer?:(
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Matt's family rented a car to go on vacation the cost of the rental was $50 plus an additional $0.20 per mile driven his family
bagirrra123 [75]
1) 300miles X $0.20 = $60

2) $50 + $60 = $110

They spent $110 for the car.
6 0
3 years ago
Y-3=-3y-43 how would i solve?​
frez [133]

Answer: y−3=−3y−43

Step 1: Add 3y to both sides.

y−3+3y=−3y−43+3y

4y−3=−43

Step 2: Add 3 to both sides.

4y−3+3=−43+3

4y=−40

Step 3: Divide both sides by 4.

4y

4

=

−40

4

y=−10

Answer:

y=−10

Step-by-step explanation: brainliest:)

7 0
3 years ago
Solve for x in the equation x 2 - 4 x - 9 = 29.
Marizza181 [45]

Answer:

x= -19

Step-by-step explanation:

2x-4x-9=29

-2x=29+9

x=38/-2

= -19

5 0
3 years ago
Read 2 more answers
. Yesterday you wanted to make an enormous batch of rolls, so you borrowed some special yeast from your aunt's top-secret bread
Cloud [144]

Answer:

at 6:06

Step-by-step explanation:

since it took 13 to be half full just add an extra 13 minutes.   5:53+ 13 minutes= 6:06

8 0
2 years ago
Find the exact values of sin2 θ for cos θ = 3/18 on the interval 0° ≤ θ ≤ 90°
mote1985 [20]

Answer:

sin(2\theta)=\frac{\sqrt{35} }{18}

Step-by-step explanation:

Recall the formula for the sine of the double angle:

sin(2\theta)=2*sin(\theta)*cos(\theta)

we know that cos(\theta)=\frac{3}{18}, and that \theta is in the interval between 0 and 90 degrees, where both the functions sine and cosine are non-negative numbers. Based on such, we can find using the Pythagorean trigonometric property that relates sine and cosine of the same angle, what sin(\theta) is:

cos^2(\theta)+sin^2(\theta)=1\\sin^2(\theta)=1-cos^2(\theta)\\sin(\theta)=\sqrt{1-cos^2(\theta)} \\sin(\theta)=\sqrt{1-(\frac{3}{18} )^2}\\sin(\theta)=\sqrt{1-\frac{9}{324} }\\sin(\theta)=\sqrt{\frac{324-9}{324} }\\sin(\theta)=\sqrt{\frac{315}{324} }\\\\sin(\theta)=\frac{3}{18}\sqrt{35 }

With this information, we can now complete the value of the sine of the double angle requested:

sin(2\theta)=2*sin(\theta)*cos(\theta)\\sin(2\theta)=2*\frac{3}{18} \,\sqrt{35} \,\frac{3}{18}\\sin(2\theta)=\frac{2*3*3}{18*18}\,\sqrt{35} \\sin(2\theta)=\frac{\sqrt{35} }{18}

6 0
2 years ago
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