Customers choose from a stack of cards to determine the discount they receive. The stack contains twenty 10% discount cards, fif
1 answer:
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Answer:
42.22% probability that the weight is between 31 and 35 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that the weight is between 31 and 35 pounds
This is the pvalue of Z when X = 35 subtracted by the pvalue of Z when X = 31. So
X = 35
has a pvalue of 0.5557
X = 31
has a pvalue of 0.1335
0.5557 - 0.1335 = 0.4222
42.22% probability that the weight is between 31 and 35 pounds
Answer:
OPTION C: y = 2x² + 1
Step-by-step explanation:
To identify the function substitute the values of 'x' and 'y' and compare LHS and RHS.
OPTION A: y = -(5x + 1)
When x = -2, y = 9
Therefore, LHS = 9
RHS = -(5(-2) + 1) = -(-10 + 1) = 9
So, LHS = RHS.
Now, we check for the second pair. i.e., (x, y) = (-1, 3)
LHS = 3
RHS = -(-5 + 1) = -(-4) = 4
LHS RHS
So, this option is eliminated.
OPTION B: y = - 4x + 1
Like OPTION A, substitute x = -2 and y = 9.
LHS = 9
RHS = - 4(-2) + 1 = 9
LHS = RHS
Now for the second pair: (-1, 3)
LHS = 3
RHS = -4(-1) + 1 = 4 + 1 = 5
We see LHS RHS.
So, this option is eliminated as well.
OPTION C: y = 2x² + 1
Substituting the first pair: (-2, 9)
LHS = 9
RHS = 2(4) + 1 = 9
So, LHS = RHS
Now For the second pair: (-1, 3)
We have LHS = 3
RHS = 2(1) + 1 = 3
LHS = RHS.
The third pair: (0, 1)
LHS = 1
RHS = 2(0) + 1 = 1
For the pair: (1, 3)
LHS = 3
RHS = 2(1) + 1 = 3
Again, LHS = RHS
For the pair: (2, 9)
LHS = 9
RHS = 2(4) + 1 = 9
Since, for all the pairs we have LHS and RHS equal, we con conclude that this is the correct representation of our function.
Similarly, substitute OPTION D. The option can be eliminated in the second pair itself.
So, the answer is OPTION C.