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Harman [31]
3 years ago
5

Which system of linear inequalities is graphed?

Mathematics
2 answers:
guapka [62]3 years ago
7 0
<h2><em>the answer is   y ≥ 3x - 1 x + 3y ≤ 6  Just took the test</em></h2>
Gnoma [55]3 years ago
7 0

Answer:

Option B

Step-by-step explanation:

To check the system of inequalities we will take a point in the shaded area of the graph.

Then we will plug in the coordinates in the inequalities to check the validity of the inequality.

Let a point in the shaded area is ( 0,1)

Option A ⇒  y < 3x - 1

                    1 < 3 × 0 - 1

                    1 < -1

                    False. So this graph is not for this system.

Option B ⇒ y > 3x - 1

                    1 > 3 ×0 - 1

                    1 > -1

                   x + 3y < 6

                   0 + 3 × 1 < 6

                   3 < 6

                  Valid for both the inequalities so the system graphed is the set                       of y > 3x - 1 and x + 3y < 6

Option C ⇒ y ≤ 3x - 1

                    1 ≤ 3 × 0 - 1

                    1 ≤ -1

                    Not valid

Option D ⇒ y ≥ 3x - 1

                     1 ≥ 3 × 0 -1

                     1 ≥ -1

                    Since 1 ≠ -1

So this point is not in the shaded area.

Therefore, Option B is the answer.

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