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kykrilka [37]
3 years ago
6

The sum of two numbers is 42 . The smaller number is 10 less than the larger number. What are the numbers?

Mathematics
2 answers:
natulia [17]3 years ago
7 0
42 = x + (x-10)
52 = 2x
/2      /2
26 = x

Therefore the numbers are:
1) 26
2) 16 (26 - 10)
polet [3.4K]3 years ago
6 0
The answer is 26 and 16
26-16=10 so thats correct
and 
26+16=42
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Exponential growth/decay problem 2
lapo4ka [179]

Answer:

a) decay

b) 2,950,000

c) 0.025

d) f(x)=2950000(0.975)^x

e) 2,409,123

Step-by-step explanation:

<u>Part (a)</u>

Exponential DECAY, since the population was decreasing annually.

<u>Part (b)</u>

Initial amount = 2,950,000 people (in the year 2000)

<u>Part (c)</u>

Decay factor = 2.5% = 0.025 (in decimal form)

<u>Part (d)</u>

General form of exponential decay function:

f(x)=a(1-r)^x

where:

  • a = initial amount
  • r = rate of decay (in decimal form)
  • x = time (in years)

Given:

  • a = 2950000
  • r = 0.025

\implies f(x)=2950000(1-0.025)^x

\implies f(x)=2950000(0.975)^x

<u>Part (e)</u>

To determine the city's population in 2008:

x = 2008 - 2000 = 8

\begin{aligned}\implies f(8) & =2950000(0.975)^8\\ & = 2409123\: \sf(nearest\:whole\:number)\end{aligned}

7 0
2 years ago
Solve<br> 10x + 4<br> = 8<br> 7<br><br> ASAP
Anettt [7]

Answer:

10x + 4/7 = 8

10x + 4 = 56

10x = 52

x = 5.2

4 0
3 years ago
What multiplies to 24 and adds to -9
d1i1m1o1n [39]
Unfortunately, there are no two such numbers.

If your original question was: \sf{x^{2} -9x+24=0} and you were trying to factor it, I would suggest the quadratic formula.

There are two solutions to \sf{ax^2+bx+c=0, where \sf{a\neq 0}<span>, and we can find them by using the quadratic formula: 
</span>
\huge{\sf{x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}}}

So using that, here is how it would get factored:

For your equation, \sf{a = 1, b = -9, c = 24}

Plug in those values into the formula:

\sf{\frac{ -(-9) \pm \sqrt{ (-9)^2 -  4 \cdot 1 \cdot 24} }{ 2 \cdot 1 }}

Simplifying it:

\sf{\frac{ 9 \pm \sqrt{ -15 } }{ 2 }}

And so the solutions are:

\sf{x_1 = \frac{ 9~+~\sqrt{ -15 } }{ 2 } = \frac{9}{2}+\frac{1}{2}\sqrt{15}i}
and
\sf{x_2 = \frac{ 9~-~\sqrt{ -15 } }{ 2 } = \frac{9}{2}-\frac{1}{2}\sqrt{15}i}
7 0
3 years ago
Read 2 more answers
Factor: 3x4y3 – 48y3
kati45 [8]

Answer:

3y3(x2 + 4)(x + 2)(x -2)

Step-by-step explanation:

3x4y3– 48y3.

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= 3y3[(x2)2 - 42].

= 3y3(x2 + 4)(x2 - 4).

= 3y3(x2 + 4)(x2 - 22).

= 3y3(x2 + 4)(x + 2)(x -2).

3 0
3 years ago
How to solve a verbal problem algebraically
jenyasd209 [6]
Step 1. You must write down/ underline all the numbers given in the problem.

Step2. Identify all the unknown variable such as x, y, a, b [those are the most common ones].

Step 3 Identify what sign of operation your working with... It can be +,-,×,÷.

Step 3 write down all your terms on the LHS of the equation.

Step 4. Equate all the constant on the RHS of the equation. If the constant was negative It would be positive and vic versa

Step. Solve your problem
5 0
4 years ago
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