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kolbaska11 [484]
3 years ago
14

F(x) = x^2. What is g(x)?

Mathematics
1 answer:
MatroZZZ [7]3 years ago
5 0

Answer:

D. g(x)=(3x)^2

Step-by-step explanation:

For function g(x), it displays the point (1,9) as part of the function. If (x,y), then we can plug those into the available answers. Plug 1 in for each x value in the function and whichever one equals 9 will be your answer. This is only true for g(x)=(3x)^2.

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2(7g - 4h) - 6(5h - 3g)
pishuonlain [190]

Answer:

32g - 38h

Step-by-step explanation:

Step 1:

14g - 8h - 30h + 18g

Step 2:

32g - 38h

Answer:

32g - 38h

Hope This Helps :)

6 0
3 years ago
Read 2 more answers
A goalie make 12 saves in 3 games. What is the rate of saves per game?
Elena L [17]

Answer:

Step-by-step explanation:

No of saves in 3 games = 12

Rate of saves per game = 12 ÷ 3 = 4

4 0
3 years ago
Suppose that we are testing H0 : 0 versus H1 : 0 with a sample size of n 10. Calculate bounds on the P-value for the following o
stepan [7]

Answer:

a) p_V = 2*P(t_{9} >|2.48|) =0.0349

We can use the following excel code: "=2*(1-T.DIST(2.48,9,TRUE))"

0.03 < p_v

b) p_V = 2*P(t_{9} >|-3.95|)=0.003355

We can use the following excel code: "=2*(1-T.DIST(3.95,9,TRUE))"

p_v

c) p_V = 2*P(t_{9} >|2.69|) =0.02480

We can use the following excel code: "=2*(1-T.DIST(2.69,9,TRUE))"

0.01 < p_v

d) p_V = 2*P(t_{9} >|1.88|) =0.09281

We can use the following excel code: "=2*(1-T.DIST(1.88,9,TRUE))"

0.05 < p_v

Step-by-step explanation:

For this case we are testing the following system of hypothesis:

Null hypothesis: \mu =0

Alternative hypothesis: \mu \neq 0

The sample size is n=10, so then the degrees of freedom are given by:

df=n-1= 10-1=9

In order to calculate the p value we can use the fact that we are conducting a bilateral test so then the p value is given by:

p_V = 2*P(t_{9} >|t_0|)

Where t_0 represent the calculated or observed statistic.

a) t0= 2.48

p_V = 2*P(t_{9} >|2.48|) =0.0349

We can use the following excel code: "=2*(1-T.DIST(2.48,9,TRUE))"

0.03 < p_v

b) t0= -3.95

p_V = 2*P(t_{9} >|-3.95|)=0.003355

We can use the following excel code: "=2*(1-T.DIST(3.95,9,TRUE))"

p_v

c) t0=2.69

p_V = 2*P(t_{9} >|2.69|) =0.02480

We can use the following excel code: "=2*(1-T.DIST(2.69,9,TRUE))"

0.01 < p_v

d) t0=1.88

p_V = 2*P(t_{9} >|1.88|) =0.09281

We can use the following excel code: "=2*(1-T.DIST(1.88,9,TRUE))"

0.05 < p_v

6 0
2 years ago
What is the Gcf for 39,6
andreev551 [17]

Answer:

The greatest common factor of these two numbers is 3

Step-by-step explanation:

To find this, look for the highest number that both can be divide by to get whole numbers.

39/3 = 13

6/3 = 2

6 0
2 years ago
A piece of string is 42 meters long. It is cut into three pieces so that one piece is 15 meters longer than the other two, which
Semmy [17]
To start this problem, we know that one of the three pieces that the string is cut into is 15 meters longer than the others. Subtract 15 from 42 to get 27.
Then, from there, you can cut that number (<em>divide</em>) by three to get the length of the two shorter strings. Simply add the 15 meters you didn't use yet to one of the pieces to find the longer string, and you have your lengths.

Hope this helps!
-refrac532
4 0
3 years ago
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