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k0ka [10]
3 years ago
13

Which of the following is the explicit rule for a geometric sequence defined by a recursive formula of for which the first term

is 7?

Mathematics
2 answers:
Lena [83]3 years ago
7 0

Answer:

  B.  an = 7·13^(n-1)

Step-by-step explanation:

The general form of the explicit rule for a geometric sequence is ...

  an = a1·r^(n-1)

The common ratio (r) is the multiplier in the recursive rule: 13. The first term (a1) is given as 7. Filling in these values, you have ...

  an = 7·13^(n-1)

__

As always, you can check the answer choices to see which one satisfies the requirements. Here, you need go no further than evaluating each of the expressions for n=1.

  A. a1 = 13·7² ≠ 7

  B. a1 = 7·1  = 7 . . . . as required

  C. a1 = 7·13² ≠ 7

  D. a1 = 13·1 ≠ 7

Allushta [10]3 years ago
4 0
.it should be C for the question
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Answer:

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Using:y-y_1=\frac{y_2-y_1}{x_2-x_1}\cdot (x-x_1)

On substituting the values in the formula above we will get the required equation of line.

y-10=\frac{15-10}{2-6}\cdot (x-6)

\Rightarrow y-10=\frac{5}{-4}\cdot (x-6)

On simplification we will get:

y=\frac{1}{4}(-5x+70)

(b) We need to tell at day 0 put x=0 in above equation:

y=\frac{1}{4}(-5\cdot 0+70)

y=70

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Now, we need to tell decrease per day which is equal to the slope of line

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3 0
3 years ago
Match the pairs of equations that represent concentric circles. Tiles
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I will explain you and pair two of the equations as an example to you. Then, you must pair the others.

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2) The equation of a circle with center xc, yc, and radius r is:

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So, if you have that equation you can inmediately tell the coordinates of the center and the radius of the circle.

3) You can transform the equations given in your picture to the form (x -xc)^2 + (y -yc)^2 = r2 by completing squares.

Example:

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rearrange: 3x^2 + 12x + 3y^2 - 6y = 21

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complete squares: (x + 2)^2 - 4 + (y - 1)^2 - 1 = 7

=> (x + 2)^2 + (y - 1)^2 = 12 => center = (-2,1), r = √12.

equation: 4x^2 + 4y^2 + 16x - 8y - 308 = 0

rearrange: 4x^2 + 16x + 4y^2 - 8y = 308

common factor 4: 4 (x^2 + 4x) + 4(y^2 -8y) = 4*77

=> (x^2 + 4x) + (y^2 - 2y) = 77

complete squares: (x + 2)^2  - 4 + (y - 1)^2 - 1 = 77

=> (x + 2)^2 + (y - 1)^2 = 82 => center = (-2,1), r = √82

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