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k0ka [10]
3 years ago
13

Which of the following is the explicit rule for a geometric sequence defined by a recursive formula of for which the first term

is 7?

Mathematics
2 answers:
Lena [83]3 years ago
7 0

Answer:

  B.  an = 7·13^(n-1)

Step-by-step explanation:

The general form of the explicit rule for a geometric sequence is ...

  an = a1·r^(n-1)

The common ratio (r) is the multiplier in the recursive rule: 13. The first term (a1) is given as 7. Filling in these values, you have ...

  an = 7·13^(n-1)

__

As always, you can check the answer choices to see which one satisfies the requirements. Here, you need go no further than evaluating each of the expressions for n=1.

  A. a1 = 13·7² ≠ 7

  B. a1 = 7·1  = 7 . . . . as required

  C. a1 = 7·13² ≠ 7

  D. a1 = 13·1 ≠ 7

Allushta [10]3 years ago
4 0
.it should be C for the question
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Answer:

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3 years ago
The degenerative disease osteoarthritis most frequently affects weight-bearing joints such as the knee. Two random samples from
Vinvika [58]

Answer:

t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771  

df=n_1 +n_2 -2=13+19-2=30  

Since is a right tailed test the p value would be:  

p_v =P(t_{30}>1.771)=0.0434  

Comparing the p value with the significance level \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the mean for group 1 is significantly higher than the mean for the group 2

Step-by-step explanation:

Data given

\bar X_{1}=810 represent the mean for sample 1  

\bar X_{2}=770 represent the mean for sample 2  

s_{1}=67 represent the sample standard deviation for 1  

s_{2}=56 represent the sample standard deviation for 2  

n_{1}=13 sample size for the group 2  

n_{2}=19 sample size for the group 2  

\alpha=0.05 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for category 1 is higher than the mean for category 2, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=13+19-2=30  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771  

P value  

Since is a right tailed test the p value would be:  

p_v =P(t_{30}>1.771)=0.0434  

Comparing the p value with the significance level \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the mean for group 1 is significantly higher than the mean for the group 2

4 0
3 years ago
Find the 10th term in the Arithmetic Sequence -2, -5, -8, -11
Inessa [10]
As you can tell, the next time decreases by three every time. So, the tenth term would be -29.
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4 0
3 years ago
Can someone help me? And possibley tell me how to solve this as well? I'm totally clueless haha
Bumek [7]

Answer:

? = 3

Step-by-step explanation:

To find the value of ?, substitute one of the ordered pairs from the table [except (0, 0)] into the given formula and solve for ?.

Given formula:

\sf y=\boxed{?} \:x

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\sf 3=\boxed{?} \:1

To isolate ? divide both sides by 1:

\implies \sf \dfrac{3}{1}=\dfrac{\boxed{?} \:1}{1}

\implies \sf 3=\boxed{?}

Therefore, ? = 3:

\implies \sf y=3x

Check by inputting another value of x from the table into the found formula and comparing the calculated y-value:

\sf x=-2 \implies y=3(-2)=-6 \quad \boxed{\sf correct}

\sf x=3 \implies y=3(3)=9 \quad \boxed{\sf correct}

5 0
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zmey [24]

Answer:

d , 10

Step-by-step explanation:

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7 0
3 years ago
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