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erma4kov [3.2K]
2 years ago
10

. Sofia learned 10 recipes to create party dishes. She learned these recipes in two weeks. How many recipes can Sofia learn in 5

weeks?
Mathematics
2 answers:
Eddi Din [679]2 years ago
5 0

Answer:

Sofia can learn 25 recipes in 5 weeks.

Step-by-step explanation:

First, to find the unit rate, we have to do 10/2 which = 5.

If the unit rate is 5 recipes per week, than she can learn 25 recipes in 5 weeks because 5 x 5 = 25

Hope this helps!

Vanyuwa [196]2 years ago
3 0

Answer:

She can learn 25 recipies

Step-by-step explanation:

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1 3/4+1/6+____=7 1/2<br> Plz help
Mademuasel [1]

Answer:

7/4 +1/6 +X=15/2

1/6+X=15/2-7/4

1/6+X=30/4-7/4

X=23/4 - 1/6

X= 138-4/24

134/24

5.58333

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
If the Federal Reserve lowers the federal funds rate, what will happen to bank savings accounts? (4 points)
mariarad [96]
The interest rate offered would decrease. The federal reserve sets the rates to help prevent inflation, deflation etc
8 0
3 years ago
Help me plzzzzzzzzzzzzzzzz i have untel 5
mojhsa [17]

Answer:

First image:

27 / 9 = 3

2.7 / 0.9 = 3

33.3/0.09 = 3

Second image:

168 / 2 = 84

16.8 / 0.2 = 84

1.68 / 0.02 = 84

7 0
3 years ago
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HELP ASAP<br> Find the 15th term or the geometric sequence 7, -21, 63,
mihalych1998 [28]
<h3><u>Answer:</u></h3>

33480783

<h2><u>Step-by-step explanation:</u></h2>

<u>Finding the Common Ratio:</u>

We know that the formula for the common ratio of a GP is:

r = aₙ / (aₙ₋₁)        <em>(Where n is any integer)</em>

<em>replacing the values, taking n=2</em>

r = -21 / 7

r = -3

<u>Solving for the 15th Term:</u>

We know that the Formula for the nth term of a GP:

G(n) = a * r ⁿ⁻¹     <em>(where a is the first term and r is the common ratio)</em>

<em>replacing the values (taking n = 15 since we need the 15th term)</em>

G(15) = 7 * (-3)¹⁴

G(15) = 33480783

Hence, the 15th term of the given GP is 33480783

5 0
3 years ago
In the previous part, we obtained dy dx = 3t2 − 27 −2t . Next, find the points where the tangent to the curve is horizontal. (En
mina [271]

Answer:

(27.55, 7.22), (-11.3, 3.21).

Step-by-step explanation:

When is the tangent to the curve horizontal?

The tangent curve is horizontal when the derivative is zero.

The derivative is:

\frac{dy}{dx} = 3t^{2} - 2t - 27

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

3t^{2} - 2t - 27 = 0

So

a = 3, b = -2, c = -27

Then

\bigtriangleup = b^{2} - 4ac = (-2)^{2} - 4*3*(-27) = 328

So

t_{1} = \frac{-(-2) + \sqrt{328}}{2*3} = 3.35

t_{2} = \frac{-(-2) - \sqrt{328}}{2*3} = -2.685

Enter your answers as a comma-separated list of ordered pairs.

We found values of t, now we have to replace in the equations for x and y.

t = 3.35

x = t^{3} - 3t = (3.35)^{3} - 3*3.35 = 27.55

y = t^{2} - 4 = (3.35)^2 - 4 = 7.22

The first point is (27.55, 7.22)

t = -2.685

x = t^{3} - 3t = (-2.685)^3 - 3*(-2.685) = -11.3

y = t^{2} - 4 = (-2.685)^2 - 4 = 3.21

The second point is (-11.3, 3.21).

8 0
3 years ago
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