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Semenov [28]
3 years ago
14

The company installing the new in-ground pool in your backyard has provided You with a scale drawing shown below. If the drawing

uses a scale of 1 inch to 1 3/4 feet, calculate the total amount of two-dimensional space needed for the pool and its surrounding patio.

Mathematics
1 answer:
Nat2105 [25]3 years ago
6 0

Answer:

The total amount of two-dimensional space needed for the pool and its surrounding is 780 feet².

Step-by-step explanation:

Consider the provided information.

The drawing uses a scale of 1 inch to 1 3/4 feet.

Now consider the figure shown.

The length and  Width of the rectangle is 22\frac{2}{7} inch and 11\frac{3}{7} inch.

22\frac{2}{7}=\frac{156}{7}

11\frac{3}{7}=\frac{80}{7}

First convert the length and width from inches to feet.

1\ inch=1\frac{3}{4}\ feet

1\ inch=\frac{7}{4}\ feet

Multiply both the sides by \frac{156}{7}

\frac{156}{7}\ inch=\frac{156}{7}\times \frac{7}{4}\ feet

\frac{156}{7}\ inch=39\ feet

Now convert \frac{80}{7} into feet.

\frac{80}{7}\ inch=\frac{80}{7}\times \frac{7}{4}\ feet

\frac{80}{7}\ inch=20\ feet

Now find the area of rectangle using the formula. A=l\times w

A=39\times 20

A=780

Hence, the total amount of two-dimensional space needed for the pool and its surrounding is 780 feet².

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Answer:

47.72% of students scored between 563 and 637 on the exam .

Step-by-step explanation:

The percentage of the students scored between 563 and 637 on the exam

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Since 563 is the mean score of students on the Statistics course, 50% of students scored lower than 563. that is P(x<563)=0.5

P(x<637)=P(z<z*) where z* is the z-statistic of the score 637.

z score can be calculated using the formula

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P(z<2)=0.9772, which means that 97.72% of students scored lower than 637 on the exam.

As a Result, 97.72%-50%=47.72% of students scored between 563 and 637 on the exam

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