What is the exact value of x in the exponential equation 22.1 + e5x = 100.1?

Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving

lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

$P(x=0) = ^nC_x P^x (1-P)^n^-^x$

$P(x=0) = ^5C_0 (0.4)^0 (1-0.4)^5^-^0$

$P(x=0) = ^5C_0 (0.4)^0 (0.60)^5$

$P(x=0) = 0.778$

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

$= 1 - P(X = 0)$

$= 1 - ^5C_0 (0.4)^0 * (0.6)^5$

$= 1 - 0.0778$

$= 0.9222$

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

$^5C_0 (0.4)^0 (0.6)^5 + ^5C_1 (0.4)^1 (0.6)^4 + ^5C_2 (0.4)^2 (0.6)^3$

$= 0.6826$

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

$= 1 - [^5C_0 (0.4)^0 (0.6)^5 + ^5C_1 (0.4)^1 (0.6)^4 + ^5C_2 * (0.4)^2 (0.6)^3]$

$= 1 - 0.6826$

$= 0.3174$

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0

3 years ago

The following data of students weights (in kg) is collected 65 48 52 55 62 58 47 53 65 71 54 62 51 49 54 60 68 53 57 62 59

tatuchka [14]

Answer:

i dont know

Step-by-step explanation:

hynmk,likujnyhbgfd

3 0

3 years ago

Help me .......................................

SpyIntel [72]

Answer:

X^3 AS THE NUMERATOR 8 AS THE DENOMINATOR

Step-by-step explanation:

6 0

3 years ago

What does 2 (p -q) +5 (p+q) equal when p = 7 and q = -2? Answer:

salantis [7]

Answer:

43

Step-by-step explanation:

Given

2(p - q) + 5(p + q) ← substitute p = 7 and q = - 2 into the expression

= 2(7 - (- 2)) + 5(7 + (- 2))

= 2(7 + 2) + 5(7 - 2)

= 2(9) + 5(5)

= 18 + 25

= 43

7 0

3 years ago

The following back to back stemplot represents the amount a sample of students spent on their last haircut. Because there are si

krek1111 [17]

The 5 - number summary of the distribution obtained from the boxplot is :

Minimum = 20
Maximum = 85
Lower quartile = 35
Median = 44
Upper quartile = 58
Outlier = 100

Firstly, we need to extract the values for the amount spent by females :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The five number summary include ;

Minimum, lower Quartile, Median, Upper Quartile and Maximum values.

Rearranging the data in ascending order :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The boxplot clearly and easily gives the five number summary of the distribution :

Minimum = 20 (starting point of the whisker)
Lower quartile = 35 (starting point of the box)
Median = 44 (vertical line in between the box)
Upper quartile = 58 (endpoint of the box)
Maximum = 85 (endpoint of the upper whisker).

Outlier :

Lower boundary = LOWER QUARTILE - (1.5 × IQR)
Upper boundary = UPPER QUARTILE + (1.5 × IQR)
IQR = UPPER QUARTILE - LOWER QUARTILE
IQR = (58 - 35) = 23

Lower boundary = 35 - (1.5 × 23) = 0.5

Upper boundary = 58 + (1.5 × 23) = 92.5

The point denoted by a dot on the boxplot is an outlier = 100

Hence, values lesser than 0.5 or greater than 92.5 are outliers.

Therefore, 100 is an outlier.

Learn more : brainly.com/question/24582786

7 0

3 years ago