Answer:
49 percent
Step-by-step explanation:
So convert the fraction into a percentage
245/500= 49%
The word "associative" comes from "associate" or "group";the Associative Property is the rule that refers to grouping. For addition, the rule is "<span>a + (b + c) = (a + b) + c</span><span>"; in numbers, this means
</span>2 + (3 + 4) = (2 + 3) + 4. For multiplication, the rule is "<span>a(bc) = (ab)c</span>"; in numbers, this means2(3×4) = (2×3)4<span>. Any time they refer to the Associative Property, they want you to regroup things; any time a computation depends on things being regrouped, they want you to say that the computation uses the Associative Property.</span>
Good afternoon,
First side= 8cm
Third side= x
Second side= 2x-4
We know that the sume of the lenghts of any two sides must be greater than the third side, so:

<span>
Answer: Third side= x ; where: x>4 or (4,+infinity) Second side= 2x-4 ; </span><span>
where: x>4 or (4,+infinity)</span>
<span>Percent of discount is 25% and the sale price is 40$ what is the original amount? $160
percent of discount is 5% and the sale price is 57$ what is the original amount? $60
percent of discount is 80% and the sale price is 90$ what is the original amount? $112.5
percent of discount is 15% and the sale price is 146.54$ what is the original
amount? $976.93
the original price is 60$ and the sale price is 45$ what is the percent of discount? 25%
original price is 82$ and the sale price is 65.60$ what is the percent of discount? 20%
original price is 95$ and the sale price is 61.75$ what is the percent of discount? 35%</span>
Answer:
Part a) The radii are segments AC and AD and the tangents are the segments CE and DE
Part b) 
Step-by-step explanation:
Part a)
we know that
A <u>radius</u> is a line from any point on the circumference to the center of the circle
A <u>tangent</u> to a circle is a straight line which touches the circle at only one point. The tangent to a circle is perpendicular to the radius at the point of tangency.
In this problem
The radii are the segments AC and AD
The tangents are the segments CE and DE
Part b)
we know that
radius AC is perpendicular to the tangent CE
radius AD is perpendicular to the tangent DE
CE=DE
Triangle ACE is congruent with triangle ADE
Applying the Pythagoras Theorem

substitute the values and solve for CE





remember that
CE=DE
so
