Answer:
280
Step-by-step explanation:
Answer:
The two scenarios differ.
P(Scenario A) = 0.107
P(Scenario B) = 0.265
Step-by-step explanation:
The two scenarios are different because for the second one you are alredy assuming that the first 3 cards are not hearths, and for that reason, B is more likely to happen that A.
For B to happen, you need to notice that since you remove 3 cards from your deck that are not hearts, then your deck has only 49 cards, and 13 of them are hearts. The probability for a heart to show up is, as a result 13/49 = 0.265 because you have 13 favourable cases from 49 possible.
For A, you need the first card to be anything but a heart. Since 13 cards of the deck are herts, 39 are not, and the probability of that hapening is 39/52 = 3/4. After you remove your first card, the probability of the second one not being heart is 38/51, and the probability for the third one is 37/50 (you are removing one favourable case and one case for the total of cases each time). The probability for the fourth card being a heart assuming that the first three are not was calculated before and it gives us a result of 13/49.
Multiplying everything, we obtain that
P(A) = 3/4*38/51*37/50*13/49 = 0.107.
Answer:
x = 5.9
Step-by-step explanation:
Step 1: Write equation
14 = 31.7 - 3x
Step 2: Solve for <em>x</em>
<u>Subtract 31.7 on both sides:</u> -17.7 = -3x
<u>Divide both sides by -3:</u> x = 5.9
Step 3: Check
<em>Plug in x to verify if it's a solution.</em>
14 = 31.7 - 3(5.9)
14 = 31.7 - 17.7
14 = 14
Answer:
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Answer:
C)
Step-by-step explanation:
