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Anuta_ua [19.1K]

2 years ago

14

Exit

2 answers:

Marrrta [24]2 years ago

5 0

Answer:

C)

Step-by-step explanation:

sattari [20]2 years ago

3 0

Answer is C
Because it explains the shape that it talks about

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21 22 23 24 25 The function f(x) is shown on the graph. What is f(0)? 0 only –6 only –2, 1, 1, and 3 only –6, –2, 1, 1, and 3 on

sertanlavr [38]

Help me please i posted it

3 0

3 years ago

Read 2 more answers

Jana ran the first 3 and a half miles of a 5 mile race in 1 3rd of an hour. what was her average rate, in mph, for the first par

Lisa [10]

Answer:

always try to draw a diagram first

Step-by-step explanation:

Jana ran The first 3.5 miles in 1/3 of an hour. remember the problem tells us that we want our answer in miles per hour or mph. so we have to set up our problem so that our units match in the end. The diagram above shows 3.5 mi over 1/3 hour. so we must divide 3.5 miles by 1/3 hour

note:

$3 \frac{1}{2} mi = \frac{7mi}{2}$

therefore

$\frac{7mi}{2} \: \div \: \frac{1hr}{3} =$

$\frac{7mi}{2} \times \frac{3}{1hr} = \frac{21mi}{2hr} = 10 \frac{1}{2} \frac{mi}{hr}$

7 0

3 years ago

-4/3 divided by (-12)

marissa [1.9K]

Answer:

0.11111111111

Step-by-step explanation:

i hope this is right! if not im sorry!

7 0

3 years ago

Read 2 more answers

Lacey runs a stable that boards a range of horses.

BartSMP [9]

Answer:

Step-by-step explanation:

8 out of 20 horses are brown

so

8/20

so

2/5

so

2/5 * 15 = 6

so

6 horses should be brown out of 15

6 0

3 years ago

(Uniform) Suppose X follows a continuous uniform distribution from 4 to 11. (a) Write down the PDF of X. (b) Find P(X ≤ 7). Roun

love history [14]

Answer:

a) $f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

b) $P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

c) $P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

d) $P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

Step-by-step explanation:

For this case we assume that the random variable X follows this distribution:

$X \sim Unif (a=4, b =11)$

Part a

The probability density function is given by the following expression:

$f(x) = \frac{1}{b-a} , a \leq x \leq b$

$f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

Part b

We want this probability:

$P(X \leq 7)$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}= \frac{x-4}{11-4}$

And replacing we got:

$P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

Part c

We want this probability:

$P(5 < X \leq 7)$

And we can use the CDF again and we have:

$P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

Part d

We want this conditional probabilty:

$P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

7 0

3 years ago