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3 years ago

Determine if the situation is a percent INCREASE or DECREASE

Mathematics

1 answer:

VashaNatasha [74]3 years ago

3 0

Answer: Decrease

Step-by-step explanation:

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Negative nine is greater than or equal to the sum of two - fifths times a number and 9.

Bumek [7]

Answer:

W is either -22.5, or less than -22.5

Step-by-step explanation:

-9>=2/5 times w (I wasn't sure what you meant by "and" 9. Like 9w?)

W has to be a negative number, or else it would be greater than 9, which would make the equation wrong.

2/5 times -22 1/2=-9. So w can be -22 1/2 or -22.5

W can then be anything "lower" (on the left side) of -22.5.

W<-22.5

5 0

3 years ago

In place value the Relationship between 2,000 and 20 is how many times

Katen [24]

Answer:

100

Step-by-step explanation:

20 times 100 equals 2000

6 0

3 years ago

If you answer this I will mark you brainliest

Temka [501]

Answer:

Here is the ans..hope it helps:)

8 0

2 years ago

Sammy's Sandwich Shop has a mean delivery time of 25 minutes with a standard deviation of 2 minutes. Determine the z-score for t

fiasKO [112]

Answer:

-1

Step-by-step explanation:

Given: Mean= 25 minutes.

Standard deviation= 2 minutes

x= 23 minutes.

Lets find the z-score for the number of sandwiches delivered in less than 23 mins.

Formula: Z-score= $\frac{x-mean}{standard\ deviation}$

Z-score= $\frac{23-25}{2}$

⇒ Z-score= $\frac{-2}{2}$

∴ Z-score will be -1

Hence, -1 is the z-score for the number of sandwiches delivered in less than 23 minutes.

6 0

3 years ago

I am offering another 100 points

Ivahew [28]

Answer:

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

Step-by-step explanation:

Perfect squares: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...

To find $\sf \sqrt{75}$ , identify the perfect squares immediately before and after 75:

64 and 81

$\begin{aligned}\sf As\;\; 64 < 75 < 81\; & \implies \sf \sqrt{64} < \sqrt{75} < \sqrt{81}\\&\implies \sf \;\;\;\;\;8 < \sqrt{75} < 9 \end{aligned}$

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

See the attachment for the correct placement of $\sf \sqrt{75}$ on the number line.

6 0

1 year ago

Read 2 more answers