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3 years ago

13

If the in-control fraction nonconforming is known to be 0.1, what is the minimum subgroup sample size n required for a nonzero l

ower control limit (LCL) of a p-chart based on three-sigma control limits?

1 answer:

Igoryamba3 years ago

7 0

Answer:

Solution is attached in the picture below

Step-by-step explanation:

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Quadrilateral DEFG has vertices at D(−2,2), E(−1,4), F(2,3), and G(−1,−2). Find the vertices of the quadrilateral after a dilati

dangina [55]

Answer: D(-7,7),E(-3.5,14),F(7,10.5), and G(-3.5, -7)

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3 years ago

The University of Central Florida's cheerleading team has eighteen males and twenty-one females. If h represents the height of a

Anuta_ua [19.1K]

Answer:

The range of heights of the cheerleaders is the interval [58, 74)

All real numbers greater than or equal to 58 inches and less than 74 inches

Step-by-step explanation:

we have

$260 \leq 4h+28$

Divide the compound inequality into two inequalities

$260 \leq 4h+28$ -----> inequality A

$4h+28$ -----> inequality B

Solve inequality A

$260 \leq 4h+28$

Subtract 28 both sides

$232 \leq 4h$

Divide by 4 both sides

$58 \leq h$

Rewrite

$h \geq 58\ in$

Solve the inequality B

$4h+28$

Subtract 28 both sides

$4h$

Divide by 4 both sides

$h$

therefore

The range of heights of the cheerleaders is the interval [58, 74)

All real numbers greater than or equal to 58 inches and less than 74 inches

3 0

3 years ago

WILL GIVE BRAINLYEST TO FIRST NEED ASAP

Harman [31]

Answer:

122

Step-by-step explanation:

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3 years ago

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Multiply the following complex numbers:<br> (9-21)(7 +61)

Andrew [12]

Answer:

-816

Step-by-step explanation:

-12*68= -816 this is probably wrong but this is what i got

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3 years ago

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Kilgore's Deli is a small delicatessen located near a major university. Kilgore does a large walk-in carry-out lunch business. T

AfilCa [17]

Answer:

z (max) = 6.15

x₁ = 1 x₂ = 3 x₃ = 6

Amount of beef leftover 2 lb

Amount of onions leftover 0

Amount of Special Sauce leftover 61

Amount of Hot Sauce leftover 9

Step-by-step explanation:

Ingredients Beef Onions Special S Hot S Profit

Wimpy (x₁) 1 2 5 0 0.6

Dial 911 (x₂) 1 2 2 5 0.55

Fire Bowl (x₃) 1.5 2 3 6 0.65

Available 15 20 90 60

Objective Function z:

z = 0.6*x₁ + 0.55*x₂ + 0.65*x₃ to maximize

Subject to:

1) Quantity of beef : 15

x₁ + x₂ + 1.5*x₃ ≤ 15

2) Quantity of onions: 20

2*x₁ + 2*x₂ + 2*x₃ ≤ 20

3) Quantity of Special sauce: 90

5*x₁ + 2*x₂ + 3*x₃ ≤ 90

4) Quantity of hot sauce: 60

0*x₁ + 5*x₂ + 6*x₃ ≤ 60

5) Condition: The number of servings for Fire Bowl must be at least 10% of the total number of servings for all three luncheon chili specials.

x₃ ≥ 0.1 ( x₁ + x₂ + x₃ ) or x₃ ≥ 0.1*x₁ + 0.1 *x₂ + 0.1*x₃

x₃ - 0.1*x₁ - 0.1 *x₂ - 0.1*x₃ ≥ 0

- 0.1*x₁ - 0.1 *x₂ + 0.9 *x₃ ≥ 0

6)Condition: The number of servings for Fire Bowl, however, cannot exceed the number of Dial 911 by more than 3.

x₃ - x₂ ≤ 3

7)the available number of servings for Dial 911 must be at least 2.

x₂ ≥ 2

General constraints:

x₁ ≥ 0 x₃ ≥ 0 all integers

With on-line solver solution is:

z (max) = 6.15

x₁ = 1 x₂ = 3 x₃ = 6

By sbstitution on the constraints

1) x₁ + x₂ + 1.5*x₃ ≤ 15 1 + 3 + 9 = 13

Amount of beef leftover 2 lb

2) 2*x₁ + 2*x₂ + 2*x₃ ≤ 20 2 + 6 + 12 = 20

Amount of onions leftover 0

3) 5*x₁ + 2*x₂ + 3*x₃ ≤ 90 5 + 6 + 18 = 29

Amount of Special Sauce leftover 61

4)0*x₁ + 5*x₂ + 6*x₃ ≤ 60 15 + 36 = 51

Amount of Hot Sauce leftover 9

3 0

2 years ago