First, you could see the amount of fence he could buy, or 144/6, which would be 24, so Mr. North can buy 24 yards of fencing.
So now to find the possible plans, we know that there are four sides, but the width and the length occur twice since it's a rectangle.
So since we know that, we can just split 24 in half to find the possibilities for one of the width sides and one of the length sides, if that makes any sense. 24/2 = 12.
So now, you could say some possibilities are length = 6 and width = 6, or length = 4 and width = 8.
And now, to consider which plan would be the best, it would probably be a 6x6 design, because it gives the biggest area to the vegetable garden, and is easy to move around.
width = 6
length = 6
area = 36 square yards (6×6)
perimeter = 24 yards (6+6+6+6)
Answer:
[-11/5,∞)
Step-by-step explanation:
1. Add 4 to both sides: 7x-4+4≥-15+2x+4
2. Simplify: 7x≥2x-11
3. Subtract 2x from both sides: 7x-2x≥2x-11-2x
4. Simplify: 5x≥-11
5. Divide both sides by 5: 5x/5≥-11/5
6. Simplify: -11/5
Answer:
The mean is also increased by the constant k.
Step-by-step explanation:
Suppose that we have the set of N elements
{x₁, x₂, x₃, ..., xₙ}
The mean of this set is:
M = (x₁ + x₂ + x₃ + ... + xₙ)/N
Now if we increase each element of our set by a constant K, then our new set is:
{ (x₁ + k), (x₂ + k), ..., (xₙ + k)}
The mean of this set is:
M' = ( (x₁ + k) + (x₂ + k) + ... + (xₙ + k))/N
M' = (x₁ + x₂ + ... + xₙ + N*k)/N
We can rewrite this as:
M' = (x₁ + x₂ + ... + xₙ)/N + (k*N)/N
and (x₁ + x₂ + ... + xₙ)/N was the original mean, then:
M' = M + (k*N)/N
M' = M + k
Then if we increase all the elements by a constant k, the mean is also increased by the same constant k.
