Question

The sum of two polynomials is why Z squared minus 3Z squared minus 4Y +4 if one of the palm will normally else is Y -4

Answer 1

Answer: $3yz^2-5y-3z^2+7$

Step-by-step explanation:

The complete exercise is:

"The sum of two polynomials is $-yz^2 -3z^2-4y + 4$. If one of the polynomials is $y - 4yz^2 - 3$, what is the other polynomial?"

By definition, the sum is the result of the addition.

According to the information given in the exercise, the polynomial  $-yz^2 -3z^2-4y + 4$ is obtained by adding the polynomial  $y - 4yz^2 - 3$ and another polynomial.

Then, you can find the other polynomial by subtracting  $y - 4yz^2 - 3$ from $-yz^2 -3z^2-4y + 4$:

$(-yz^2 -3z^2-4y + 4)-(y - 4yz^2 - 3)$

So, the steps are:

1. You must distribute the negative sign:

$=-yz^2 -3z^2-4y + 4-y + 4yz^2+ 3$

2. Finally, you need to add the like terms:

$=3yz^2-5y-3z^2+7$