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Andrew [12]
3 years ago
13

Liza is driving to her sister's house 360 miles away. After 4 hours, Liza is 2 3 of the way there.

Mathematics
1 answer:
DochEvi [55]3 years ago
4 0

Liza is driving to her sister's house 360 miles away. After 4 hours, Liza is 2/3 of the way there.   How many more hours  does Liza have to drive?

<em><u>Answer:</u></em>

Liza need to drive 2 more hours to reach her sister house

<em><u>Solution:</u></em>

Given that Liza is driving to her sister's house 360 miles away

So total distance = 360 miles

After 4 hours, Liza is 2/3 of the way there.

\frac{2}{3} r d \text { of total distance }=\frac{2}{3} \times 360=240

So Liza has covered 240 miles in 4 hours

Let us find the speed

<em><u>The relation between distance and speed is given as:</u></em>

speed = \frac{distance}{time}

speed = \frac{240}{4} = 60

Thus speed = 60 miles per hour

Assuming speed is same throughout the journey, let us calculate the time taken to complete remaining distance

Remaining distance = 360 - 240 = 120 miles

Now distance = 120 miles and speed = 60 miles per hour

time taken = \frac{distance}{speed}\\\\time taken = \frac{120}{60} = 2

Thus Liza need to drive 2 more hours to reach her sister house

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The top and bottom margins of a poster 66 cm each, and the side margins are 44 cm each. If the area of the printed material on t
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Answer:

  • width: 24 cm
  • height: 36 cm

Step-by-step explanation:

When margins are involved, the smallest area will be the one that has its dimensions in the same proportion as the margins. If x is the "multiplier", the dimensions of the printed area are ...

  (4x)(6x) = 384 cm^2

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The printed area is 4x by 6x, so is 16 cm by 24 cm. With the margins added, the smallest poster will be ...

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_____

<em>Comment on margins</em>

It should be obvious that if both side margins are 4 cm, then the width of the poster is 8 cm more than the printed width. Similarly, the 6 cm top and bottom margins make the height of the poster 12 cm more than the height of the printed area.

_____

<em>Alternate solution</em>

Let w represent the width of the printed area. Then the printed height is 384/w, and the total poster area is ...

  A = (w+8)(384/w +12) = 384 +12w +3072/w +96

Differentiating with respect to w gives ...

  A' = 12 -3072/w^2

Setting this to zero and solving for w gives ...

  w = √(3072/12) = 16 . . . . matches above solution.

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<em>Generic solution</em>

If we let s and t represent the side and top margins, and we use "a" for the printed area, then the above equation becomes the symbolic equation ...

  A = (w +s)(a/w +t)

  A' = t - sa/w^2

For A' = 0, ...

  w = √(sa/t)

and the height is ...

  a/w = a/√(sa/t) = √(ta/s)

Then the ratio of width to height is ...

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  width/height = s/t . . . . . . the premise we started with, above

6 0
3 years ago
The hypotenuse of a right triangle is 37 units long. Find the other two sides if the perimeter of the triangle is 84 units. Sepa
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Answer:

The lengths of the legs are 12 and 35 units

Step-by-step explanation:

Let c represent the hypotenuse and a and b represent the legs.  Then the Pythagorean Theorem requires that a^2 + b^2 = c^2 = 37^2 = Hypotenuse^2

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Then a^2 + b^2 = 37^2 becomes (47 - b)^2 + b^2 = 37^2, or 1369.  Therefore:

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Simplifying by combining like terms, we get:  

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Reducing all terms by division by 2, we get:

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The discriminant is therefore b^2 - 4ac, or 529, whose square root is ± 23.

Then the b values of this quadratic in b are

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             2

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Thus, a = 12 and b = 35, and c is given:  37.

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The lengths of the legs are 12 and 35 units.

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Answer:

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Step-by-step explanation:

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Solving :

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