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3 years ago

Which of the following defines liquid measure?

Mathematics

2 answers:

Sphinxa [80]3 years ago

8 0

Units used to measure the volume of liquids, such as water, gasoline, and milk'this the correct answer

Dmitry [639]3 years ago

4 0

What is the “Following”

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I dont know the answer to this question

DanielleElmas [232]

The dimension of the above figure is 9ft×3ft×6ft The home work wants you to recognize where the length, width , and height of the prism. the length runs along the base, the width is the smallest side on this figure, and the height always runs up and down. All the answers below should be circled:
3ft×6ft×3ft
9ft×6ft×1ft

9ft×3ft×3ft does not apply because 6 factored by a third is 2 not 3.

7 0

2 years ago

Share with your peers the null and alternative hypotheses for a decision that is relevant to your life. This can be a personal i

k0ka [10]

Answer:

Check the explanation

Step-by-step explanation:

The average amount of the exercise hours at the same time as I am at my home town is 50 hours a month

Does this diverge from average exercise while I am not in my home town? This is 46 hours

So,

Null: H0: μ = 30

H1: μ ≠ 30

Two tail test

Formula:

z = (46 - 50)/SD

7 0

3 years ago

Rose can run 4 miles in 56 minutes how many miles does Rosa run if she runs for 42 minutes

kogti [31]

$\frac{56}{42} = \frac{4}{x}$ then you figure out what you divide 56 by to get 4. which is 14. then you divide 42 by the same number 14.

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{

Jlenok [28]

Answer:

$x>2$

Step-by-step explanation:

When given the following inequality;

$(x^2+x-3):(x^2-4)\geq1$

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

$\frac{x^2+x-3}{x^2-4}\geq1$

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

$\frac{x^2+x-3}{x^2-4}-1\geq0$

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

$\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0$

Perform the operation on the other side distribute the negative sign and combine like terms;

$\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0$

Factor the equation so that one can find the intervales where the inequality is true;

$\frac{x+1}{(x-2)(x+2)}\geq0$

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

$-1, 2, -2$

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

$x\leq-2\\-2$

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

$x\leq-2$ -> negative