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shusha [124]
3 years ago
13

Pls answer this there's a pic above​

Mathematics
2 answers:
Mademuasel [1]3 years ago
8 0

Answer:

five line segment =AB,AC,AD,BC,BD,CD

AysviL [449]3 years ago
6 0

Answer:

<u>Line segments:</u>

AB, CD, BC, AD, AC.

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3x + 4y = 27 5x - 3y = 16
Arturiano [62]

Answer:

x = 5 , y = 3

Step-by-step explanation:

Solve the following system:

{3 x + 4 y = 27 | (equation 1)

5 x - 3 y = 16 | (equation 2)

Swap equation 1 with equation 2:

{5 x - 3 y = 16 | (equation 1)

3 x + 4 y = 27 | (equation 2)

Subtract 3/5 × (equation 1) from equation 2:

{5 x - 3 y = 16 | (equation 1)

0 x+(29 y)/5 = 87/5 | (equation 2)

Multiply equation 2 by 5/29:

{5 x - 3 y = 16 | (equation 1)

0 x+y = 3 | (equation 2)

Add 3 × (equation 2) to equation 1:

{5 x+0 y = 25 | (equation 1)

0 x+y = 3 | (equation 2)

Divide equation 1 by 5:

{x+0 y = 5 | (equation 1)

0 x+y = 3 | (equation 2)

Collect results:

Answer:  {x = 5 , y = 3

4 0
3 years ago
Simplify 27^2.<br><br> please (thxx)
adoni [48]

Answer:

729

Step-by-step explanation:

Raise 27 to the power of 2.

729

4 0
3 years ago
Consider the equation 2/5y = 20. Tell whether each statement is true or false
svlad2 [7]

Answer:

A. True
B. False
C. False
D. True

Step-by-step explanation:

3 0
2 years ago
Lines 3x-2y+7=0 and 6x+ay-18=0 is perpendicular. What is the value of a?
BlackZzzverrR [31]

Answer:

\boxed{\sf a = 9 }

Step-by-step explanation:

Two lines are given to us which are perpendicular to each other and we need to find out the value of a . The given equations are ,

\sf\longrightarrow 3x - 2y +7=0

\sf\longrightarrow 6x +ay -18 = 0

Step 1 : <u>Conver</u><u>t</u><u> </u><u>the </u><u>equations</u><u> in</u><u> </u><u>slope</u><u> intercept</u><u> form</u><u> </u><u>of</u><u> the</u><u> line</u><u> </u><u>.</u>

\sf\longrightarrow y = \dfrac{3x}{2} +\dfrac{ 7 }{2}

and ,

\sf\longrightarrow y = -\dfrac{6x }{a}+\dfrac{18}{a}

Step 2: <u>Find </u><u>the</u><u> </u><u>slope</u><u> of</u><u> the</u><u> </u><u>lines </u><u>:</u><u>-</u>

Now we know that the product of slope of two perpendicular lines is -1. Therefore , from Slope Intercept Form of the line we can say that the slope of first line is ,

\sf\longrightarrow Slope_1 = \dfrac{3}{2}

And the slope of the second line is ,

\sf\longrightarrow Slope_2 =\dfrac{-6}{a}

Step 3: <u>Multiply</u><u> </u><u>the </u><u>slopes </u><u>:</u><u>-</u><u> </u>

\sf\longrightarrow \dfrac{3}{2}\times \dfrac{-6}{a}= -1

Multiply ,

\sf\longrightarrow \dfrac{-9}{a}= -1

Multiply both sides by a ,

\sf\longrightarrow (-1)a = -9

Divide both sides by -1 ,

\sf\longrightarrow \boxed{\blue{\sf a = 9 }}

<u>Hence </u><u>the</u><u> </u><u>value</u><u> of</u><u> a</u><u> </u><u>is </u><u>9</u><u> </u><u>.</u>

8 0
2 years ago
Can anyone help me on this please or give the answer thank you?
Anna71 [15]

Answer:

Step-by-step explanation:

6 0
3 years ago
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