If y varies directly as x, and y is 12 when x is 1.2, what is the constant of variation for this relation?
1 answer:
Answer: 10
Step-by-step explanation:
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Step-by-step explanation:
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Answer:
7x+4
Step-by-step explanation:
Distribute:
=(3)(4x)+(3)(−2)+−5x+10
=12x+−6+−5x+10
Combine Like Terms:
=12x+−6+−5x+10
=(12x+−5x)+(−6+10)
=7x+4
All it did was shrink in size and move to the square diagonal from it
Answer:
35/4
Step-by-step explanation:
Answer:
1 4+p
2 5-(y×3)
3 m÷10
4 3×(7-d)
