Please indicate exponentiation using " ^ " Thanks.
f(x)=x2+14x+40 => <span>f(x)=x^2+14x+40
Next, complete the square:
</span>f(x)=x^2+14x+ 49 - 49 +40 = (x+7)^2 - 9
Write this in the form y = (x+7)^2 - 9 or y + 9 = (x+7)^2
Comparing this result to y = a(x-h)^2 + k, we see that h = -7 and k=-9
In vertex form, the equation is y + 9 = (x+7)^2 and the vertex is at (-7, -9).
A b and 3 is the correct answer
Its 3,167 hope this helped
<h3>Answer:</h3>
All acute angles are 72.5°; all obtuse angles are 107.5°.
<h3>Explanation:</h3>
Angles on the same side of a transversal cutting parallel lines have measures that total 180°. If o and a represent the measures of the obtuse and acute angles, respectively, then we have ...
... o + a = 180
... o - a = 35
Adding these two equations gives ...
... 2o = 215
... 215/2 = o = 107.5 . . . . degrees
Then the other angle is ...
... a = 107.5 - 35 = 72.5 . . . . degrees
_____
All corresponding angles have the same measures. All vertical angles have the same measures. So the 8 angles that arise from the intersection of the transversal with these two parallel lines will have one or the other of these two measures.
