Answer:

Step-by-step explanation:
According to Rolle's Theorem, if f(a) = f(b) in an interval [a, b], then there must exist at least one <em>c</em> within (a, b) such that f'(c) = 0.
We are given that g(5) = g(8) = -9. Then according to Rolle's Theorem, there must be a <em>c</em> in (5, 8) such that g'(c) = 0.
So, differentiate the function. We can take the derivative of both sides with respect to <em>x: </em>
<em />
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Differentiate:

Let g'(x) = 0:

Solve for <em>x</em>. First, divide everything by negative seven:

Factor:
<h3>

</h3>
Zero Product Property:

Solve for each case. Hence:

Since the first solution is not within our interval, we can ignore it.
Therefore:

Answer:
c=2
Step-by-step explanation:
7-4c=3c-7
7+7=3c+4c
14=7c
Dividing both sides by 7
c=2
CHECK:
Putting c in the above equation
7-4(2)=3(2)-7
7-8=6-7
-1=-1
Hence the above solution satisfies the given equation
Answer:its b
first off its a straight line ill give it that but its not going through the origin is think its b
hoped this helped lmk if it did
Answer:
Step-by-step explanation:
a/b=4/5 b/c=2/9
Ration of a to c is
a/c=4/9
Answer:
y = 6x + 0
Step-by-step explanation:
Equation of a line
y = mx + c
Given
( 0 , 0) ( -1/2 , -3)
find the slope m
m = y2 - y1 / x2 - x1
x1 = 0
y1 = 0
x2 = -1/2
y2 = -3
Insert the values
m = y2 - y1 / x2 - x1
m = -3 - 0 / -1/2 - 0
= -3/-1/2
Minus cancels minus
= 3/1/2
= 3/1 ÷ 1/2
= 3/1 × 2/1
= 6/1
= 6
m = 6
Substitute any of the two points given into the equation of a line
y = mx + c
Where
y - intercept point y
x - intercept point x
m - slope of the line
c - intercept
(-1/2 , -3)
x = -1/2
y = -3
-3 = 6(-1/2) + c
-3 = -6/2 + c
-3 = -3 + c
-3 + 3 = c
c = 0
y = 6x + 0
The equation of the line is
y = 6x + 0