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Andrej [43]
2 years ago
8

Please help me need to revise for a testtt!!!!

Mathematics
2 answers:
LekaFEV [45]2 years ago
5 0
You need to collect the like terms (aka the letters) so 3a-5a goes together to give -2a and 2w-9w which gives -7w so the answer is -2a-7w
LUCKY_DIMON [66]2 years ago
3 0
Remember you can add like terms exg, 3y+4y=7y 3y^2+4y^2=7y^2, but cannot add 3y^2 and 4y, or 3 and 4y so

3a+2w-5a-9w
group like trems
3a-5a+2w-9w
subtract
-2a-7w


3y^2+2w^2-y^2-w^2
group like terms (think of w^2 and y^2 as 1w^2 and 1y^2)
3y^2-y^2+2w^2-w^2
subtract
2y^2+w^2

2x+2x=4x
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2 years ago
Which products result in a perfect square trinomial? select three options. (negative x 9)(negative x minus 9) (x y x)(x y x) (2
erastovalidia [21]

The products that result in a perfect square trinomial is (x + y + x)(x + y + x), (2x - 3)(-3 + 2x) and (4y² + 25)(25 + 4y²)

<h3>What is an polynomial?</h3>

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4 0
1 year ago
WILL GIVE BRAINLIEST What is the perimeter of the track, in meters? Use π = 3.14 and round to the nearest hundredth of a meter.
Ivenika [448]

Answer:

Perimeter = 317 m

Step-by-step explanation:

Given track is a composite figure having two semicircles and one rectangle.

Perimeter of the given track = Circumference of two semicircles + 2(length of the rectangle)

Circumference of one semicircle = πr  [where 'r' = radius of the semicircle]

                                                       = 25π

                                                       = 25 × 3.14

                                                       = 78.5 m

Length of the rectangle = 80 m

Perimeter of the track = 2(78.5) + 2(80)

                                     = 157 + 160

                                     = 317 m

Therefore, perimeter of the track = 317 m

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3 years ago
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the anwser is going to be A

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