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Dmitry_Shevchenko [17]
2 years ago
11

HELP ASAP FOR BRAINLIEST:

Mathematics
2 answers:
padilas [110]2 years ago
5 0

Answer:

The answer is 12

Step-by-step explanation:

t5 = 24 = a × r⁴

t8 = 3 = a × r⁷

We divide one by the other

r³= 1 / 8

r = 1 / 2

t6 = a × r⁵ = t5 × r = 24 × (1/2) = 12.

Therefore the sixth term of the geometric sequence is 12

seropon [69]2 years ago
4 0
T5-24. T6-17. T7-10. T8-3........... it goes down by 7
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The volume of a cone is 50 pi cubic feet. Its height is 6 feet. In feet, what is the radius of the cone? Round the answer to the
defon

Answer:

Radius= 5.0ft ( given)

Step-by-step explanation:

Given: Volume of cone= 50π ft^3

Height of cone= 6ft

Required: Radius

Volume of cone= 1/3 * π * r^2 *h

(or)

r^2= Volume *3/h π ( Just disintegrating the formula and taking radius^2 to the left hand side(L.H.S) )

= (50 π *3)/(6)π

= 50/2 (because, 3 π /6 π = 1/2)

r^2 = 25

now, r =√25= 5.0 ft

Therefore, the radius of the cone is 5.0 ft(to the nearest tenth) :)

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3 years ago
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What is the value of the rational expression below when x is equal to 3 (17+x)\(x+2)
elena55 [62]

The value of the expression is 4.


We can find this by taking the original equation and plugging in 3 every time we see an x.


\frac{17 + x}{x + 2}

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2 years ago
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The aggregate annual rainfall at a given location is modeled as a random variable, resulting in a sequence of random variables {
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The outer angle at the top C of the ABC is 112 °. If the bisector of the side AB intersects the side AC at point Q and the segme
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Step-by-step explanation:

The outer angle at the top C of the ABC is 112 °. If the bisector of the side AB intersects the side AC at point Q and the segment BQ is perpendicular to AC, find the magnitude of ABC

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2 years ago
Help me! Answer in pic not correct !
sladkih [1.3K]

Answer:

Q'=(4,1)\\R'=(6,-5)\\S'=(3,-4)\\T'=(1,-1)

Step-by-step explanation:

First we have to find the coordinates of the original ordered pairs then we will do the translation.

Q=(1,3)\\R=(3,-3)\\S=(0,-2)\\T=(-2,1)

Now we will add 3 to every x value and add a -2 to every y value.

Q=(1_{+3},3_{+(-2)})\\R=(3_{+3},-3_{+(-2)})\\S=(0_{+3},-2_{+(-2)})\\T=(-2_{+3},1_{+(-2)})

When you do that you will get the new prime points.

Q'=(4,1)\\R'=(6,-5)\\S'=(3,-4)\\T'=(1,-1)

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