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Dmitry_Shevchenko [17]
3 years ago
11

HELP ASAP FOR BRAINLIEST:

Mathematics
2 answers:
padilas [110]3 years ago
5 0

Answer:

The answer is 12

Step-by-step explanation:

t5 = 24 = a × r⁴

t8 = 3 = a × r⁷

We divide one by the other

r³= 1 / 8

r = 1 / 2

t6 = a × r⁵ = t5 × r = 24 × (1/2) = 12.

Therefore the sixth term of the geometric sequence is 12

seropon [69]3 years ago
4 0
T5-24. T6-17. T7-10. T8-3........... it goes down by 7
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Is 1 3/23 a rational number
UkoKoshka [18]

Answer:

Yes

Step-by-step explanation:

In mathematics rational means "ratio like." so a rational number is one that can be written as the ratio of two integers. 1 3/23 can be converted into 26/23, which is a ratio, therefore, 1 3/23 is a rational number.

Hope this helps!

4 0
3 years ago
A train traveling south leaves the station at a constant rate of 62 kilometers per hour. A second train traveling north leaves t
malfutka [58]

Answer: 3.5 hours

Step-by-step explanation:

68 + 62 = 130

455 / 130 = 3.5

Hope this helps you! :)

7 0
3 years ago
Read 2 more answers
A right triangle in which one acute angle is a reference angle for a 75° angle in standard position intersects the unit circle a
vampirchik [111]

Alright, lets get started.

Please take a look at the diagram attached.

The reference angle of 75 will be 75

As it is mentioned that the angle intersects the unit circle means r = 1

So, finding cos

cos 75 = \frac{X}{r}

cos 75 = \frac{0.259}{1}

cos 75 = 0.259    :   Answer

Hope it will help :)


7 0
3 years ago
What’s -2f-3=7 I cant figure it out
iVinArrow [24]

Answer:

12

Step-by-step explanation:

-2f-3=7

+2f-3=7+2

f-3=9

f+3=9+3

f=12

i think

8 0
4 years ago
Read 2 more answers
Teen obesity:
Law Incorporation [45]

Answer:

95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

Step-by-step explanation:

We are given that 15% of a random sample of 300 U.S. public high school students were obese.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

                        P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample % of U.S. public high school students who were obese = 15%

           n = sample of U.S. public high school students = 300

           p = population percentage of all U.S. public high school students

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

<u></u>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                             of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

  = [ 0.15-1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } } , 0.15+1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } } ]

  = [0.110 , 0.190]

Therefore, 95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

6 0
3 years ago
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