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3 years ago

What is solution of 8x-2y =1 and -4x+y = 3

Mathematics

1 answer:

Maksim231197 [3]3 years ago

6 0

Answer: it has no solution

Step-by-step explanation:

8x - 2y = 1 ..................... equation 1

-4x + y = 3 ...................... equation 2

solving the system of linear equation by substitution method . From equation 2 , make y the subject of the formula.

y = 3 + 4x .......................... equation 3

substitute equation 3 into equation 1 .

8x - 2(3 + 4x ) = 1

8x - 6 - 8x = 1

8x- 8x - 6 = 1

-6 = 1

this means that the equation has no solution

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3.452 × 100 =-------------

Lilit [14]

Answer:

345.2

Step-by-step explanation:

1: Move 3.452 to the end of the equation

(3.452 × 100) -> (3.452 × 100 = 3.452)

2: Since 100 has 2 zeros, move the decimal point 2 places to the right.

(3.452 × 100 = 3.452) -> (345.2)

Hope this helps!

7 0

3 years ago

Read 2 more answers

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

2 years ago

The scores on a test are normally distributed with a mean of 210 and a standard deviation of 20. What is the score that is 1 dev

telo118 [61]

Answer:The score above the mean is 50 percent.

Step-by-step explanation:

8 0

1 year ago

Domino's is having a sale where everything has a 10% discount. The regular price of a 2 topping pizza is $8. What is the discoun

Aleonysh [2.5K]

Answer:

7.20

Step-by-step explanation:

7 0

2 years ago

Divide: 8x^3 y^5 / 4x^2 y^3

prisoha [69]

$2 {x}^{5} {y}^{8}$

Step-by-step explanation:

yes

3 0

1 year ago