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tatyana61 [14]
3 years ago
13

Como parte de la propuesta de investigación de Iris, ella planifica desplazar un objeto a 5 m con la fuerza de 20N. Al probar su

experimento, Iris terminó realizando un trabajo de 100 unidades. ¿Cuál unidad de medida debe usar Iris para expresar el trabajo?
Mathematics
1 answer:
ICE Princess25 [194]3 years ago
4 0

Answer:

Joule.

Step-by-step explanation:

Dado que las unidades empleadas son del Sistema Internacional, la unidad a emplear es el Joule, cuya definición es Newton multiplicado por metro.

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P is a prime number.<br> Show that p²+6 could be either even or odd
storchak [24]

<em>p</em> ² + 6 is even if <em>p</em> ² is even (the sum of two even numbers is even), and this happens only if <em>p</em> itself is even, i.e. if <em>p</em> = 2 since 2 is the only even prime.

All other primes <em>p</em> are odd, so <em>p</em> ² would be odd, and adding 6 would not change that (odd + even = odd).

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3 years ago
I'm giving brainliest to the most helpful answer. For 50 points:
Alenkinab [10]

Answer:

1) \displaystyle\frac{5}{18}\approx27.78\%

2) \displaystyle\frac{4}{7}\approx57.14\%

3) \displaystyle  \frac{13}{16}=81.25\%

Step-by-step explanation:

We are given a two-way frequency table. Using the table, we will determine the probability for each case.

Question 1)

P(A Student With A Part Time Job Without A Car)

Using the first column, the total number of students that have a part time job is 78+30=108.

Likewise, using the first column, we can see that out of those 108 students, 30 do not have a car.

Hence, the probability that a student with a part time job without a car is:

\displaystyle P=\frac{30}{108}=\frac{5}{18}\approx27.78\%

Question 2)

P(No Car | Does Not Have A Part Time Job)

Remember that the vertical line means conditional probability.

So, we want the probability of a student having no car given that they do not have a part time job.

Using the second column, we can see that the total number of students that do not have a part time job is 18+24=42.

Likewise, using the second column, 24 do not have a car.

Hence, the probability that a student with a part time job without a car is:

\displaystyle P=\frac{24}{42}=\frac{4}{7}\approx57.14\%

Question 3)

P(Part Time Job | Car)

So, we want to probability of a student having a part time job given that they have a car.

Using the first row, the total students that have a car is 78+18=96.

And of those 96 students, 78 have a part time job.

Hence, the probability that a student with a car has a part time job is given by:

\displaystyle P=\frac{78}{96}=\frac{13}{16}=81.25\%

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Step-by-step explanation:

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