Allele frequency is determined by looking at the dominant and recessive allele of a genotype.
Using the given, we can come up with the following computation for the allele frequency:
allele A = 100/300 allele B = 50/300 allele O = 150/300
Hence, the frequency of allele A is 0.33 or 33%, allele B is .17 or 17% and allele O is 0.50 or 50%.
Answer:
The correct answer is- A) two, B) yes, the number is the same as monosaccharides.
Explanation:
There are three atoms are present in a molecule of water which includes two atoms of the hydrogen and one atom of the oxygen. The hydrogen atom is two times larger in the number of the oxygen atom in a single molecule of the water.
In monosaccharides, the ratio of the atoms of carbon, hydrogen, and oxygen is 1:2:1 which means one hydrogen atom would be twice in the number of the carbon and oxygen atoms in a single molecule of monosaccharide molecule.
Thus, the correct answer is - A) two, B) yes, the number is the same as monosaccharides.
There are chances of 75% solid green coloured rind in watermelons.
Explanation:
Dominant trait = Solid Green rind G
Recessive trait= stripes g
Given that both the parent plants are heterozygous so their alleles will be
Gg Gg
From the Punnet square
G g
G GG Gg
g Gg gg
The phenotype ratio is 3:1 ( 3 watermelons with the green colour rind and 1 with striped rind observed)
Genotype ratio is 1:2:1
From the observation, we can say that 75% of the watermelons will have solid green colour rind because G is dominant over g.
Answer:
Use 400 x in order to study the structure clearly.
Explanation:
Cell structures could be clearly identified when magnify the microscope about 400 x by using a compound microscope. Due to high magnification power of compound microscope, the individual is able to see different structures that are present in cells. while by using lower magnification, the individual is unable to see different structures clearly. So use high magnification in order to study the cell.
