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3 years ago

TIMED TEST WILL GIVE BRAINLIEST

Mathematics

2 answers:

kow [346]3 years ago

5 0

Answer: 12?

Step-by-step explanation:

Tanzania [10]3 years ago

5 0

Answer: 12
Explanation: 2piR = circumference so to find just radius take out 2pi so you would do 24pi/2pi and cancel out the pi and simplify the 24/2 to just 12 :)

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5 0

2 years ago

A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the

Alex777 [14]

112 dallors interest beca0.02x + 0.04(800) = 112 0.02x + 0.04(x + 800) = 112 0.04x + 0.02(x + 800) = 112 use

6 0

4 years ago

Read 2 more answers

Which of the following can represent the three angles in an obtuse, scalene triangle?

Bingel [31]

Answer:

30, 30, 120

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

H(x)=-|x|; Find h(6)

Alik [6]

Answer:

-6

Step-by-step explanation:

-|6|=-6

5 0

1 year ago

Plz help me!!!

Nadya [2.5K]

To solve this we are going to use the exponential function: $f(t)=a(1(+/-)b)^t$
where
$f(t)$ is the final amount after $t$ years
$a$ is the initial amount
$b$ is the decay or grow rate rate in decimal form
$t$ is the time in years

Expression A
$f(t)=624(0.95)^{4t}$
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate $b$ , we are going to use the formula: $b=|1-base|$ *100%
$b=|1-0.95|$ *100%
$b=0.05$ *100%
$b=$ 5%
We can conclude that expression A decays at a rate of 5% every three months.

Now, to find the initial value of the function, we are going to evaluate the function at $t=0$
$f(t)=624(0.95)^{4t}$
$f(0)=624(0.95)^{0t}$
$f(0)=624(0.95)^{0}$
$f(0)=624(1)$
$f(0)=624$
We can conclude that the initial value of expression A is 624.

Expression B
$f(t)=725(1.12)^{3t}$
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
$b=|1-base|$ *100%
$b=|1-1.12|$ *100
$b=|-0.12|$ *100%
$b=0.12$ *100%
$b=$ 12%
We can conclude that expression B grows at a rate of 12% every 4 months.

Just like before, to find the initial value of the expression, we are going to evaluate it at $t=0$
$f(t)=725(1.12)^{3t}$
$f(0)=725(1.12)^{0t}$
$f(0)=725(1.12)^{0}$
$f(0)=725(1)$
$f(0)=725$
The initial value of expression B is 725.

We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months.

- Expression A has an initial value of 624, while expression B has an initial value of 725.

8 0

3 years ago