Slope formula: y2-y1/x-x1
We can use the given points to solve.
3-(-3)/7-5
6/2
3
Best of Luck!
Hello there,
From Point A to Point B Peter traveled roughly 30 miles in 30 minutes.
From Point B to Point C Peter traveled roughly 130 miles in 2 hours and 30 minutes.
From Point C he didn't move in distance but the hours moved so c is out.
From Point C to Point D, Peter traveled roughly 180 miles in 3 hours.
Therefore D Peter had the fastest interval at D.
Answer:
y = 460 miles per hr
x = 500 miles per hr
Step-by-step explanation:
Let the planes be X any
Let their speeds be xmiles/hr and ymiles/hr respectively
x = y + 40 (assuming X is faster by 40miles/hr)
Distance travelled by X to meet Y = 0.75x
Distance travelled by Y to meet X = 0.75y
0.75x + 0.75y = 720 --------1
Put x = y + 40 in eqn 1
0.75(y+40) + 0.75y = 720
0.75y + 30 + 0.75y= 720
1.5y = 690
y = 460 miles per hr
x = 460 +40
= 500 miles per hr
Answer:
Statement 3: DC=CD (Common)
Step-by-step explanation:
According from the statement given, consider ΔADC and ΔBCD, we get
AD=BC(opposite sides of a rectangle are congruent)
∠ADC=∠BCD(angles of a rectangle are 90°)
DC=CD(Common)
Thus, by SAS rule, ΔADC≅ΔBCD and by CPCTC AC=BD.
Thus, Statement 3 that is using the common sides of the triangle jimmy can prove the proof.
Answer:
8.06
Step-by-step explanation:
