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dexar [7]
3 years ago
10

Bored anyone wanna talk? or do a zo om?​

Mathematics
2 answers:
Serga [27]3 years ago
3 0

Answer:

Step-by-step explanation:

⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣧⣀⣀⣾⣿⣿⣿⣿

⣿⣿⣿⣿⣿⡏⠉⠛⢿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡿⣿

⣿⣿⣿⣿⣿⣿⠀⠀⠀⠈⠛⢿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⠿⠛⠉⠁⠀⣿

⣿⣿⣿⣿⣿⣿⣧⡀⠀⠀⠀⠀⠙⠿⠿⠿⠻⠿⠿⠟⠿⠛⠉⠀⠀⠀⠀⠀⣸⣿

⣿⣿⣿⣿⣿⣿⣿⣷⣄⠀⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⣴⣿⣿

⣿⣿⣿⣿⣿⣿⣿⣿⣿⠏⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠠⣴⣿⣿⣿⣿

⣿⣿⣿⣿⣿⣿⣿⣿⡟⠀⠀⢰⣹⡆⠀⠀⠀⠀⠀⠀⣭⣷⠀⠀⠀⠸⣿⣿⣿⣿

⣿⣿⣿⣿⣿⣿⣿⣿⠃⠀⠀⠈⠉⠀⠀⠤⠄⠀⠀⠀⠉⠁⠀⠀⠀⠀⢿⣿⣿⣿

⣿⣿⣿⣿⣿⣿⣿⣿⢾⣿⣷⠀⠀⠀⠀⡠⠤⢄⠀⠀⠀⠠⣿⣿⣷⠀⢸⣿⣿⣿

⣿⣿⣿⣿⣿⣿⣿⣿⡀⠉⠀⠀⠀⠀⠀⢄⠀⢀⠀⠀⠀⠀⠉⠉⠁⠀⠀⣿⣿⣿

⣿⣿⣿⣿⣿⣿⣿⣿⣧⠀⠀⠀⠀⠀⠀⠀⠈⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢹⣿⣿

⣿⣿⣿⣿⣿⣿⣿⣿⣿⠃⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⣿⣿

LOL

Anni [7]3 years ago
3 0
Dude , that pikachu up there looking mighty fine
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What is an algebraic expression for the word phrase the product of 11 and a number s?
Rainbow [258]
" the product " means multiply

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Mrs. Kang gave Caleb a collection of 25 marbles. Each month Caleb adds 4 marbles to his collection. Which inequality can be used
GarryVolchara [31]

Answer:

I did the math and got an answer of 17.5

Step-by-step explanation:

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The base of a solid in the region bounded by the two parabolas y2 = 8x and x2 = 8y. Cross sections of the solid perpendicular to
Usimov [2.4K]

The two curves intersect at two points, (0, 0) and (8, 8):

x^2=8y\implies y=\dfrac{x^2}8

y^2=\dfrac{x^4}{64}=8x\implies\dfrac{x^4}{64}-8x=0\implies\dfrac{x(x-8)(x^2+8x+64)}{64}=0

\implies x=0,x=8\implies y=0,y=8

The area of a semicircle with diameter d is \dfrac{\pi d^2}8. The diameter of each cross-section is determined by the vertical distance between the two curves for any given value of x between 0 and 8. Over this interval, y^2=8x\implies y=\sqrt{8x} and \sqrt{8x}>\dfrac{x^2}8, so the volume of this solid is given by the integral

\displaystyle\frac\pi8\int_0^8\left(\sqrt{8x}-\dfrac{x^2}8\right)^2\,\mathrm dx=\frac{288\pi}{35}

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3 years ago
Please help, ASAP thank you very much. Benton has an extension ladder than can only be used at a length of 10 feet, 15 feet, or
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The answer is a because<span>
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3 years ago
How do you do this trig problem.
loris [4]

Consider a right triangle in which one of the angles \theta satisfies

\sin\theta=\dfrac35\implies\theta=\sin^{-1}\dfrac35

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\cos\theta=\dfrac45

because

\sin^2\theta+\cos^2\theta=\dfrac9{25}+\dfrac{16}{25}=1

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